If
[tex]\[ A=\begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}, \quad B=\begin{bmatrix} 1 & 2 \\ 0 & 3 \end{bmatrix} \][/tex]
find:
[tex]\[ A^{\top} + B \][/tex]



Answer :

To solve the problem, let's follow these steps in detail:

1. Identify the given matrices: We start with the matrices [tex]\( A \)[/tex] and [tex]\( B \)[/tex].

Matrix [tex]\( A \)[/tex] is:
[tex]\[ A = \begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix} \][/tex]

Matrix [tex]\( B \)[/tex] is:
[tex]\[ B = \begin{pmatrix} 1 & 2 \\ 0 & 3 \end{pmatrix} \][/tex]

2. Find the transpose of matrix [tex]\( A \)[/tex]: The transpose of a matrix is obtained by flipping it over its diagonal, which means switching the row and column indices of the matrix.

So, the transpose of [tex]\( A \)[/tex] (denoted as [tex]\( A^\top \)[/tex]) is:
[tex]\[ A^\top = \begin{pmatrix} 1 & 3 \\ 2 & 4 \end{pmatrix} \][/tex]

3. Add the transpose of [tex]\( A \)[/tex] to matrix [tex]\( B \)[/tex]: Matrix addition involves adding corresponding elements from each matrix.

Adding [tex]\( A^\top \)[/tex] and [tex]\( B \)[/tex] element-wise:

[tex]\[ A^\top + B = \begin{pmatrix} 1 & 3 \\ 2 & 4 \end{pmatrix} + \begin{pmatrix} 1 & 2 \\ 0 & 3 \end{pmatrix} \][/tex]

To perform this addition:
- Add the elements in the first row, first column: [tex]\( 1 + 1 = 2 \)[/tex]
- Add the elements in the first row, second column: [tex]\( 3 + 2 = 5 \)[/tex]
- Add the elements in the second row, first column: [tex]\( 2 + 0 = 2 \)[/tex]
- Add the elements in the second row, second column: [tex]\( 4 + 3 = 7 \)[/tex]

Thus, the result is:
[tex]\[ A^\top + B = \begin{pmatrix} 2 & 5 \\ 2 & 7 \end{pmatrix} \][/tex]

Therefore, the final result of adding the transpose of [tex]\( A \)[/tex] to [tex]\( B \)[/tex] is:
[tex]\[ \begin{pmatrix} 2 & 5 \\ 2 & 7 \end{pmatrix} \][/tex]

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