The pOH of a solution is 10.75. What is the concentration of [tex]$OH^{-}$[/tex] ions in the solution?

Use [tex]$\left[ OH^{-} \right] = 10^{- \text{pOH}}$[/tex].

A. [tex]3.162 \times 10^{-108}[/tex] M
B. [tex]1.778 \times 10^{-11}[/tex] M
C. [tex]1.075 \times 10^2[/tex] M
D. [tex]5.623 \times 10^{10}[/tex] M



Answer :

To determine the concentration of hydroxide ions ([tex]\(OH^-\)[/tex]) in a solution given its pOH, we use the formula:

[tex]\[ [OH^{-}] = 10^{- \text{pOH}} \][/tex]

Let's go through the steps to solve this problem:

1. You are given the pOH of the solution as 10.75.
2. Using the formula, [tex]\([OH^{-}] = 10^{- \text{pOH}}\)[/tex], we substitute the given pOH value into the equation:

[tex]\[ [OH^{-}] = 10^{-10.75} \][/tex]

3. Evaluating this expression results in a numerical value for the concentration of [tex]\(OH^{-}\)[/tex] ions:

[tex]\[ [OH^{-}] = 1.778 \times 10^{-11} \text{ M} \][/tex]

Therefore, the concentration of [tex]\(OH^{-}\)[/tex] ions in the solution is [tex]\(1.778 \times 10^{-11} \text{ M}\)[/tex].

Among the given options, the correct answer is:

[tex]\[ 1.778 \times 10^{-11} \text{ M} \][/tex]

Other Questions