A 30.0-g goldfinch lands on a slender branch, where it oscillates up and down with simple harmonic motion of amplitude 3.50 x 10⁻² m and period 1.50s. At the time when the goldfinch experiences its maximum acceleration, is its speed a maximum or a minimum?



Answer :

Answer:

In simple harmonic motion (SHM), the acceleration of the oscillating object is maximum when the displacement is zero (at the equilibrium position), and it is minimum (zero) when the displacement is maximum (at the amplitude).

Given:

Amplitude (

A) of oscillation =

3.50

×

1

0

2

3.50×10

−2

 m

Period (

T) of oscillation = 1.50 s

At the time when the goldfinch experiences its maximum acceleration, it is at the equilibrium position (displacement

=

0x=0).

To determine whether the speed (velocity magnitude) of the goldfinch is a maximum or minimum at this point:

At the equilibrium position (

=

0

x=0), the velocity of the goldfinch is maximum. This is because the velocity is zero at the amplitude (where displacement is maximum), and it increases as the goldfinch moves towards the equilibrium position.

Therefore, at the time when the goldfinch experiences its maximum acceleration (which occurs at the equilibrium position

= 0

x=0), its speed (velocity magnitude) is a maximum.

Explanation: