Answer :
Sure! To convert the number [tex]\( 0.0602 \times 10^{25} \)[/tex] into proper scientific notation, we need to express the number in the form [tex]\( a \times 10^b \)[/tex], where [tex]\( a \)[/tex] (the coefficient) is a number greater than or equal to 1 and less than 10, and [tex]\( b \)[/tex] (the exponent) is an integer.
Here are the steps:
1. Identify the number and the exponent: The starting number is [tex]\( 0.0602 \)[/tex] and the exponent is [tex]\( 25 \)[/tex].
2. Normalize the coefficient: We need to change [tex]\( 0.0602 \)[/tex] to a number between 1 and 10. We can do this by moving the decimal place one position to the right, converting [tex]\( 0.0602 \)[/tex] to [tex]\( 0.602 \)[/tex].
3. Adjust the exponent: Since we moved the decimal point one place to the right, we need to decrease the exponent by 1. The original exponent was [tex]\( 25 \)[/tex], so the new exponent will be [tex]\( 24 \)[/tex].
Thus, the number [tex]\( 0.0602 \times 10^{25} \)[/tex] in proper scientific notation is:
[tex]\[ 0.602 \times 10^{24} \][/tex]
So, in the green box you should enter [tex]\( 0.602 \)[/tex], and in the yellow box you should enter [tex]\( 24 \)[/tex].
Here are the steps:
1. Identify the number and the exponent: The starting number is [tex]\( 0.0602 \)[/tex] and the exponent is [tex]\( 25 \)[/tex].
2. Normalize the coefficient: We need to change [tex]\( 0.0602 \)[/tex] to a number between 1 and 10. We can do this by moving the decimal place one position to the right, converting [tex]\( 0.0602 \)[/tex] to [tex]\( 0.602 \)[/tex].
3. Adjust the exponent: Since we moved the decimal point one place to the right, we need to decrease the exponent by 1. The original exponent was [tex]\( 25 \)[/tex], so the new exponent will be [tex]\( 24 \)[/tex].
Thus, the number [tex]\( 0.0602 \times 10^{25} \)[/tex] in proper scientific notation is:
[tex]\[ 0.602 \times 10^{24} \][/tex]
So, in the green box you should enter [tex]\( 0.602 \)[/tex], and in the yellow box you should enter [tex]\( 24 \)[/tex].