Enter the data to create a histogram. Then check all that apply.

Data:
\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|}
\hline
runs & 1 & 7 & 1 & 6 & 1 & 2 & 8 & 6 & 8 & 0 \\
\hline
\end{tabular}

The histogram has:
A. 1 cluster.
B. 2 clusters.
C. 1 peak.
D. 4 peaks.
E. 0 frequency from [tex]$4-5$[/tex].



Answer :

Let’s analyze the given data step by step to determine the number of clusters, peaks, and investigate the frequency from 4-5.

### Step-by-step Solution:

1. Data Entry and Histogram Creation:
The provided data is:
1, 7, 1, 6, 1, 2, 8, 6, 8, 0

We will first calculate the frequency of each number to create a histogram:
- Frequency of 0: 1
- Frequency of 1: 3
- Frequency of 2: 1
- Frequency of 6: 2
- Frequency of 7: 1
- Frequency of 8: 2

So the histogram looks like this:
[tex]\[ \begin{align*} 0 & : 1 \\ 1 & : 3 \\ 2 & : 1 \\ 6 & : 2 \\ 7 & : 1 \\ 8 & : 2 \\ \end{align*} \][/tex]

2. Calculating Clusters:
Clusters are groups of consecutive numbers in the histogram. We analyze the sorted keys: [0, 1, 2, 6, 7, 8]:

- Cluster 1: 0
- Cluster 2: 1, 2
- Gap (indicates the end of the first cluster)
- Cluster 3: 6, 7, 8

Therefore, we have 2 clusters.

3. Calculating Peaks:
Peaks are points where the frequency increases, makes a peak, and then might decrease. Here, we count distinct frequency peaks:

- Peak 1: 1 (Frequency of 1: 3)
- Peak 2: 6 (Frequency of 6: 2)
- Peak 3: 8 (Frequency of 8: 2)

So, we have 3 peaks.

4. Frequency from 4 to 5:
We specifically check if there are any numbers with frequency between 4 and 5:

- 4 is not in the data
- 5 is not in the data

Therefore, there is 0 frequency from 4 to 5.

Based on the analysis, let's check the statements:

- The histogram has [tex]\( \textbf{1 cluster}\)[/tex] – Incorrect.
- The histogram has [tex]\( \textbf{2 clusters}\)[/tex] – Correct.
- The histogram has [tex]\( \textbf{1 peak}\)[/tex] – Incorrect.
- The histogram has [tex]\( \textbf{4 peaks}\)[/tex] – Incorrect.
- The histogram has [tex]\( \textbf{0 frequency from 4-5}\)[/tex] – Correct.

Thus, the correct statements after analyzing the histogram are:
- The histogram has 2 clusters.
- The histogram has 0 frequency from 4-5.