Find the value of [tex]\( x \)[/tex] that makes the function [tex]\( f(x) = \frac{1}{\left(\frac{3}{2}\right)^{2-x}} \)[/tex] equal to [tex]\( h \)[/tex].

[tex]\[
f(x) = \frac{1}{\left(\frac{3}{2}\right)^{2-x}}
\][/tex]

Given [tex]\( h \)[/tex], solve for [tex]\( x \)[/tex].



Answer :

Sure! Let's find the simplified form of the given function:
[tex]$ f(x)=\frac{1}{\left(\frac{3}{2}\right)^{2-x}} $[/tex]

Step 1: Understand the function notation.

The given function can be interpreted as:
[tex]$ f(x) = \frac{1}{\left(\left(\frac{3}{2}\right)\right)^{2-x}} $[/tex]

Step 2: Recall the rule of exponents that says [tex]\(\frac{a}{b} = a \cdot b^{-1}\)[/tex].

```math
\frac{3}{2} = 1.5 (approximated value)
```
Therefore:
[tex]$ \left(\frac{3}{2}\right)^{2-x} = 1.5^{2-x} $[/tex]

Step 3: Apply the law of exponents:
[tex]$ f(x)=\frac{1}{1.5^{2-x}} ``` which can be written as: ```math f(x)=1.5^{- (2-x)} ``` Simplifying further gives: $[/tex]f(x)=1.5^{x-2}
[tex]$ Therefore, the simplified form of the given function is: $[/tex]
\boxed{1.5^{x-2}}
[tex]$[/tex]