Answer :
Sure! Let's solve the given chemical equation step-by-step for balancing it and determining the moles of each substance involved.
### Step 1: Write the Unbalanced Equation
The given chemical reaction is:
[tex]\[ \text{Na}_2(s) + \text{Cl}_2(g) \longrightarrow \text{NaCl}_{(s)} \][/tex]
### Step 2: Identify the Number of Each Type of Atom on Both Sides
In the unbalanced equation:
- On the left-hand side, we have:
- Sodium (Na): 2 atoms from Na₂
- Chlorine (Cl): 2 atoms from Cl₂
- On the right-hand side, we have:
- Sodium (Na): 1 atom from NaCl
- Chlorine (Cl): 1 atom from NaCl
### Step 3: Balance the Equation
To balance the equation, we need to ensure that the number of each type of atom is the same on both sides.
#### Balancing Sodium (Na):
- Since there are 2 sodium atoms on the reactant side (Na₂) and 1 sodium atom on the product side (NaCl), we need to have 2 NaCl molecules to balance the sodium atoms.
[tex]\[ \text{Na}_2(s) + \text{Cl}_2(g) \longrightarrow 2\text{NaCl}_{(s)} \][/tex]
#### Balancing Chlorine (Cl):
- Now, check the number of chlorine atoms.
- On the left side, we have 2 chlorine atoms from Cl₂.
- On the right side, we now have 2 chlorine atoms in 2 NaCl (each NaCl has 1 chlorine atom).
### Step 4: Verify the Balanced Equation
Finally, let's verify to ensure that both sides of the equation have the same number of each type of atom.
- Left-hand side:
- Na: 2 (from Na₂)
- Cl: 2 (from Cl₂)
- Right-hand side:
- Na: 2 (from 2 NaCl)
- Cl: 2 (from 2 NaCl)
Everything is balanced now.
### Conclusion
The balanced equation is:
[tex]\[ \text{Na}_2(s) + \text{Cl}_2(g) \longrightarrow 2\text{NaCl}_{(s)} \][/tex]
This implies:
- 1 mole of Na₂ reacts with 1 mole of Cl₂ to produce 2 moles of NaCl.
Thus, the result is:
- 1 mole of [tex]\(\text{Na}_2\)[/tex]
- 1 mole of [tex]\(\text{Cl}_2\)[/tex]
- 2 moles of [tex]\(\text{NaCl}\)[/tex]
So, when asked for the coefficients of the balanced equation, we have:
[tex]\[ (1, 1, 2) \][/tex]
### Step 1: Write the Unbalanced Equation
The given chemical reaction is:
[tex]\[ \text{Na}_2(s) + \text{Cl}_2(g) \longrightarrow \text{NaCl}_{(s)} \][/tex]
### Step 2: Identify the Number of Each Type of Atom on Both Sides
In the unbalanced equation:
- On the left-hand side, we have:
- Sodium (Na): 2 atoms from Na₂
- Chlorine (Cl): 2 atoms from Cl₂
- On the right-hand side, we have:
- Sodium (Na): 1 atom from NaCl
- Chlorine (Cl): 1 atom from NaCl
### Step 3: Balance the Equation
To balance the equation, we need to ensure that the number of each type of atom is the same on both sides.
#### Balancing Sodium (Na):
- Since there are 2 sodium atoms on the reactant side (Na₂) and 1 sodium atom on the product side (NaCl), we need to have 2 NaCl molecules to balance the sodium atoms.
[tex]\[ \text{Na}_2(s) + \text{Cl}_2(g) \longrightarrow 2\text{NaCl}_{(s)} \][/tex]
#### Balancing Chlorine (Cl):
- Now, check the number of chlorine atoms.
- On the left side, we have 2 chlorine atoms from Cl₂.
- On the right side, we now have 2 chlorine atoms in 2 NaCl (each NaCl has 1 chlorine atom).
### Step 4: Verify the Balanced Equation
Finally, let's verify to ensure that both sides of the equation have the same number of each type of atom.
- Left-hand side:
- Na: 2 (from Na₂)
- Cl: 2 (from Cl₂)
- Right-hand side:
- Na: 2 (from 2 NaCl)
- Cl: 2 (from 2 NaCl)
Everything is balanced now.
### Conclusion
The balanced equation is:
[tex]\[ \text{Na}_2(s) + \text{Cl}_2(g) \longrightarrow 2\text{NaCl}_{(s)} \][/tex]
This implies:
- 1 mole of Na₂ reacts with 1 mole of Cl₂ to produce 2 moles of NaCl.
Thus, the result is:
- 1 mole of [tex]\(\text{Na}_2\)[/tex]
- 1 mole of [tex]\(\text{Cl}_2\)[/tex]
- 2 moles of [tex]\(\text{NaCl}\)[/tex]
So, when asked for the coefficients of the balanced equation, we have:
[tex]\[ (1, 1, 2) \][/tex]