A country's population in 1994 was 76 million. In 1998 it was 81 million. Estimate the population in 2016 using the exponential growth formula. Round your answer to the nearest million.

The exponential growth formula is given by:
[tex] P = A e^{k t} [/tex]

Enter the correct answer.



Answer :

To estimate the population of a country in the year 2016, using its population data from the years 1994 and 1998, we can apply the exponential growth formula:

[tex]\[ P = A e^{kt} \][/tex]

where:
- [tex]\( P \)[/tex] is the population at time [tex]\( t \)[/tex].
- [tex]\( A \)[/tex] is the initial population.
- [tex]\( k \)[/tex] is the growth rate.
- [tex]\( t \)[/tex] is the time in years.

### Step 1: Identify the known values
- Initial population in 1994: [tex]\( A = 76 \)[/tex] million
- Population in 1998: [tex]\( P = 81 \)[/tex] million
- The time span between 1994 and 1998: [tex]\( t = 1998 - 1994 = 4 \)[/tex] years
- Target year for population estimate: 2016

### Step 2: Find the growth rate [tex]\( k \)[/tex]

First, we rearrange the exponential growth formula to solve for the growth rate [tex]\( k \)[/tex]:

[tex]\[ P = A e^{kt} \][/tex]
[tex]\[ \frac{P}{A} = e^{kt} \][/tex]
[tex]\[ \ln\left(\frac{P}{A}\right) = kt \][/tex]
[tex]\[ k = \frac{1}{t} \ln\left(\frac{P}{A}\right) \][/tex]

Substituting the known values:

[tex]\[ P = 81 \, \text{million} \][/tex]
[tex]\[ A = 76 \, \text{million} \][/tex]
[tex]\[ t = 4 \, \text{years} \][/tex]

[tex]\[ k = \frac{1}{4} \ln\left(\frac{81}{76}\right) \][/tex]

From the result, we know:

[tex]\[ k \approx 0.015928953596526945 \, \text{(per year)} \][/tex]

### Step 3: Estimate the population in 2016

Now we use the exponential growth formula again to find the population in 2016.

Let's calculate the time span from 1994 to 2016:

[tex]\[ t_{\text{target}} = 2016 - 1994 = 22 \, \text{years} \][/tex]

Using the exponential growth formula:

[tex]\[ P = A e^{kt_{\text{target}}} \][/tex]

Substitute the values:

[tex]\[ A = 76 \, \text{million} \][/tex]
[tex]\[ k \approx 0.015928953596526945 \, \text{(per year)} \][/tex]
[tex]\[ t_{\text{target}} = 22 \, \text{years} \][/tex]

[tex]\[ P = 76 \cdot e^{0.015928953596526945 \cdot 22} \][/tex]

From the result, we know:

[tex]\[ P \approx 107.89627181144573 \, \text{million} \][/tex]

Rounding to the nearest million:

[tex]\[ P = 108 \, \text{million} \][/tex]

### Answer:
The estimated population in 2016 is [tex]\(\boxed{108 \, \text{million}}\)[/tex].