Jalen randomly chooses a number from 1 to 10. What is the probability he chooses a number greater than 3?

A. [tex]$\frac{1}{5}$[/tex]
B. [tex]$\frac{7}{10}$[/tex]
C. [tex]$\frac{7}{9}$[/tex]
D. [tex]$\frac{3}{5}$[/tex]



Answer :

Let's solve the problem step-by-step to determine the probability that Jalen chooses a number greater than 3 from the numbers 1 to 10.

### Step 1: List the total numbers in the range

The numbers Jalen can choose from are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10

In total, there are 10 numbers.

### Step 2: Identify the numbers greater than 3 in this range

The numbers greater than 3 in this range are:
4, 5, 6, 7, 8, 9, 10

We can count these numbers to find how many there are:
1. 4
2. 5
3. 6
4. 7
5. 8
6. 9
7. 10

There are 7 numbers greater than 3.

### Step 3: Calculate the probability

The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.

In this case, the number of favorable outcomes (numbers greater than 3) is 7, and the total number of possible outcomes (all numbers from 1 to 10) is 10.

So, the probability [tex]\( P \)[/tex] that Jalen chooses a number greater than 3 is:

[tex]\[ P = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{7}{10} \][/tex]

### Conclusion

The probability that Jalen chooses a number greater than 3 from 1 to 10 is [tex]\( \frac{7}{10} \)[/tex].

Looking at the given options:
- A. [tex]\( \frac{1}{5} \)[/tex]
- B. [tex]\( \frac{7}{10} \)[/tex]
- C. [tex]\( \frac{7}{9} \)[/tex]
- D. [tex]\( \frac{3}{5} \)[/tex]

The correct answer is:
B. [tex]\( \frac{7}{10} \)[/tex]