To determine the correct net ionic equation for the reaction between calcium hydroxide ([tex]\(Ca(OH)_2\)[/tex]) and sulfuric acid ([tex]\(H_2SO_4\)[/tex]), we need to follow these steps:
1. Write the balanced molecular equation:
[tex]\[
Ca(OH)_2 + H_2SO_4 \longrightarrow CaSO_4 + 2H_2O
\][/tex]
2. Write the complete ionic equation:
[tex]\[
Ca^{2+}(aq) + 2OH^-(aq) + 2H^+(aq) + SO_4^{2-}(aq) \longrightarrow CaSO_4(s) + 2H_2O(l)
\][/tex]
3. Identify and remove the spectator ions:
Spectator ions are ions that appear on both sides of the complete ionic equation without undergoing any chemical change. In this case, [tex]\(Ca^{2+}\)[/tex] and [tex]\(SO_4^{2-}\)[/tex] are spectator ions.
4. Write the net ionic equation by excluding the spectator ions:
[tex]\[
2OH^-(aq) + 2H^+(aq) \longrightarrow 2H_2O(l)
\][/tex]
Simplifying this, we divide by 2:
[tex]\[
OH^-(aq) + H^+(aq) \longrightarrow H_2O(l)
\][/tex]
Therefore, the correct net ionic equation for the given reaction is:
[tex]\[
H^+ + OH^- \longrightarrow H_2O
\][/tex]
Hence, the correct answer is:
[tex]\[
\boxed{H^+ + OH^- \longrightarrow H_2O}
\][/tex]
