Which is the second step of the fusion process?

A. [tex]\({ }_1^1 H + { }_1^1 H \rightarrow { }_1^2 H + e^{+} + v + \text{ energy} \)[/tex]

B. [tex]\( 6\left({ }_1^1 H \right) + 2\left({ }_{-1}^0 e \right) \rightarrow { }_2^4 He + 2\left({ }_1^1 H \right) + \text{ energy} + 2 v \)[/tex]

C. [tex]\({ }_1^2 H + { }_1^1 H \rightarrow { }_2^3 He + \text{ energy} \)[/tex]

D. [tex]\({ }_2^3 He + { }_2^3 He \rightarrow { }_2^4 He + { }_1^1 H + { }_1^1 H + \text{ energy} \)[/tex]



Answer :

The fusion process that powers the sun and other stars primarily involves the conversion of hydrogen into helium through a series of reactions. Let's outline the major steps in one of the simplest fusion cycles known as the proton-proton chain reaction (P-P chain):

1. First Step: Two protons ([tex]\( {}_1^1H \)[/tex]) collide and fuse to form a deuterium nucleus ([tex]\( {}_1^2H \)[/tex]), a positron ([tex]\( e^+ \)[/tex]), and a neutrino ([tex]\( \nu \)[/tex]):
[tex]\[ {}_1^1H + {}_1^1H \rightarrow {}_1^2H + e^+ + \nu + \text{energy} \][/tex]

2. Second Step: A deuterium nucleus ([tex]\( {}_1^2H \)[/tex]) collides with a proton ([tex]\( {}_1^1H \)[/tex]) to produce a helium-3 nucleus ([tex]\( {}_2^3He \)[/tex]) and releases energy:
[tex]\[ {}_1^2H + {}_1^1H \rightarrow {}_2^3He + \text{energy} \][/tex]

3. Third Step: Two helium-3 nuclei ([tex]\( {}_2^3He \)[/tex]) collide and fuse to form a helium-4 nucleus ([tex]\( {}_2^4He \)[/tex]) and two protons ([tex]\( {}_1^1H \)[/tex]), releasing energy:
[tex]\[ {}_2^3He + {}_2^3He \rightarrow {}_2^4He + 2 {}_1^1H + \text{energy} \][/tex]

Now, examining the provided options for the full fusion process, we can see that the second step corresponds to:
[tex]\[ {}_1^2H + {}_1^1H \rightarrow {}_2^3He + \text{energy} \][/tex]

This is the second reaction in the proton-proton chain fusion process.