Answer :
To determine the molarity of the given KCl solution, we need to follow these steps:
1. Find the moles of KCl:
First, we need to calculate the number of moles of KCl. We can do this by using the formula:
[tex]\[ \text{moles of KCl} = \frac{\text{mass of KCl}}{\text{molar mass of KCl}} \][/tex]
Given data:
- Mass of KCl = 8.45 g
- Molar mass of KCl = 74.55 g/mol
Substituting the values:
[tex]\[ \text{moles of KCl} = \frac{8.45 \text{ g}}{74.55 \text{ g/mol}} \approx 0.113 \][/tex]
So, the moles of KCl are approximately [tex]\(0.113 \text{ mol}\)[/tex].
2. Calculate the molarity of the solution:
The molarity (M) is calculated using the formula:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]
Given data:
- Volume of the solution = 0.750 L
Substituting the values:
[tex]\[ \text{Molarity (M)} = \frac{0.113 \text{ mol}}{0.750 \text{ L}} \approx 0.151 \text{ M} \][/tex]
Therefore, the molarity of the solution is approximately [tex]\(0.151 \text{ M}\)[/tex].
From the provided options, the correct molarity is:
[tex]\[ \boxed{0.151 \text{ M}} \][/tex]
1. Find the moles of KCl:
First, we need to calculate the number of moles of KCl. We can do this by using the formula:
[tex]\[ \text{moles of KCl} = \frac{\text{mass of KCl}}{\text{molar mass of KCl}} \][/tex]
Given data:
- Mass of KCl = 8.45 g
- Molar mass of KCl = 74.55 g/mol
Substituting the values:
[tex]\[ \text{moles of KCl} = \frac{8.45 \text{ g}}{74.55 \text{ g/mol}} \approx 0.113 \][/tex]
So, the moles of KCl are approximately [tex]\(0.113 \text{ mol}\)[/tex].
2. Calculate the molarity of the solution:
The molarity (M) is calculated using the formula:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]
Given data:
- Volume of the solution = 0.750 L
Substituting the values:
[tex]\[ \text{Molarity (M)} = \frac{0.113 \text{ mol}}{0.750 \text{ L}} \approx 0.151 \text{ M} \][/tex]
Therefore, the molarity of the solution is approximately [tex]\(0.151 \text{ M}\)[/tex].
From the provided options, the correct molarity is:
[tex]\[ \boxed{0.151 \text{ M}} \][/tex]