To determine the number of grams of NaCl required to prepare a 250.0 mL solution with a molarity of 3.000 M, follow these steps:
1. Understand the given variables:
- Molarity ([tex]\( M \)[/tex]) is 3.000 mol/L.
- Volume ([tex]\( V \)[/tex]) is 250.0 mL.
- The molar mass of NaCl is 58.44 g/mol.
2. Convert the volume from milliliters to liters:
[tex]\[
\text{Volume in liters} = \frac{\text{Volume in mL}}{1000} = \frac{250.0}{1000} = 0.250 \text{ L}
\][/tex]
3. Calculate the number of moles of NaCl required:
[tex]\[
\text{Moles of NaCl} = \text{Molarity} \times \text{Volume in liters} = 3.000 \text{ mol/L} \times 0.250 \text{ L} = 0.750 \text{ mol}
\][/tex]
4. Convert the moles of NaCl to grams using the molar mass:
[tex]\[
\text{Mass of NaCl} = \text{Moles of NaCl} \times \text{Molar mass of NaCl} = 0.750 \text{ mol} \times 58.44 \text{ g/mol} = 43.83 \text{ g}
\][/tex]
Thus, to make 250.0 mL of a 3.000 M NaCl solution, you need 43.83 grams of NaCl.
