Let's break down the problem and solve it step-by-step:
1. Define Variables:
- Let [tex]\( x \)[/tex] be the cost of each sandwich in dollars.
2. Set Up the Inequality:
- Charlie wants to order 6 sandwiches and a \[tex]$2 kid's meal.
- The total cost for the sandwiches will be \( 6x \).
- The total cost he can spend is \$[/tex]32.
- Including the kid's meal, the inequality to model this situation is:
[tex]\[
6x + 2 \leq 32
\][/tex]
3. Solve the Inequality:
- Subtract 2 from both sides to isolate the term with [tex]\( x \)[/tex]:
[tex]\[
6x + 2 - 2 \leq 32 - 2
\][/tex]
Simplifying, we get:
[tex]\[
6x \leq 30
\][/tex]
- Divide both sides by 6 to solve for [tex]\( x \)[/tex]:
[tex]\[
x \leq \frac{30}{6}
\][/tex]
Simplifying, we find:
[tex]\[
x \leq 5
\][/tex]
Thus, Charlie can spend up to \[tex]$5 on each sandwich for the 6 sandwiches and still remain within his budget of \$[/tex]32 including the kid's meal.
4. Select the Correct Answers:
- The inequality that models this situation correctly is:
[tex]\[
6x + 2 \leq 32
\][/tex]
- The correct answer for how much Charlie can spend on each sandwich is:
[tex]\[
\$5 \text{ or less}
\][/tex]
Therefore, the correct selections are:
- F. Inequality: [tex]\( 6x + 2 \leq 32 \)[/tex]
- C. Answer: [tex]\( \$5 \text{ or less} \)[/tex]
