Type the correct answer in each box.

Solve the problems. Express your answers to the correct number of significant figures.

[tex]\[
\begin{array}{l}
\frac{2.31}{0.790}=\square \\
\left(2.08 \times 10^3\right) \times \left(3.11 \times 10^2\right)=\square \times 10^5
\end{array}
\][/tex]



Answer :

Sure, let's solve each problem step-by-step.

1. For the division problem:
[tex]\[ \frac{2.31}{0.790} = \square \][/tex]
We need to divide 2.31 by 0.790.

The result of this division, expressed to the correct number of significant figures, is:
[tex]\[ \frac{2.31}{0.790} = 2.924 \][/tex]

2. For the multiplication problem:
[tex]\[ (2.08 \times 10^3) \times (3.11 \times 10^2) = \square \times 10^5 \][/tex]
First, multiply the coefficients:
[tex]\[ 2.08 \times 3.11 = 6.4688 \][/tex]

Next, multiply the powers of 10:
[tex]\[ 10^3 \times 10^2 = 10^5 \][/tex]

So the multiplication result in scientific notation, expressed to the correct number of significant figures, is:
[tex]\[ (2.08 \times 10^3) \times (3.11 \times 10^2) = 6.469 \times 10^5 \][/tex]

To summarize, the solutions are:
[tex]\[ \frac{2.31}{0.790} = 2.924 \][/tex]
[tex]\[ (2.08 \times 10^3) \times (3.11 \times 10^2) = 6.469 \times 10^5 \][/tex]