\begin{tabular}{|l|l|l|l|l|l|}
\hline
1.9 & 2.2 & 2.2 & 2.2 & 2.4 & 1.9 \\
\hline
107 & 108 & 109 & 110 & 111 & 112 \\
\hline
Bh & Hs & Mt & Ds & Rg & Cn \\
\hline
\end{tabular}

Which pair of elements can form ionic bonds?

A. copper [tex]$( Cu )$[/tex] and nitrogen [tex]$( N )$[/tex]
B. gallium (Ga) and phosphorus (P)
C. hydrogen [tex]$( H )$[/tex] and sulfur [tex]$( S )$[/tex]
D. phosphorus (P) and fluorine (F)
E. potassium [tex]$( K )$[/tex] and bromine [tex]$( Br )$[/tex]



Answer :

To determine which pair of elements can form ionic bonds, we need to recognize the nature of the elements involved. Ionic bonds typically form between metals and non-metals, where the metal donates one or more electrons to the non-metal, resulting in positively charged cations and negatively charged anions which are attracted to each other.

Examining each pair:

A. Copper (Cu) and Nitrogen (N)
- Copper is a metal, and nitrogen is a non-metal. In some cases, Cu can form ionic compounds, but more often with elements where the electron transfer is more favorable.

B. Gallium (Ga) and Phosphorus (P)
- Gallium is a metal, and phosphorus is a non-metal. Gallium often forms covalent bonds rather than ionic bonds.

C. Hydrogen (H) and Sulfur (S)
- Hydrogen is a non-metal (though it can act like a metal under certain conditions), and sulfur is a non-metal. Typically, they form covalent rather than ionic bonds.

D. Phosphorus (P) and Fluorine (F)
- Both phosphorus and fluorine are non-metals. They tend to form covalent bonds with each other rather than ionic bonds.

E. Potassium (K) and Bromine (Br)
- Potassium is a metal, and bromine is a non-metal. Potassium readily loses one electron to form a K+ cation, and bromine accepts one electron to form a Br- anion. This electron transfer creates an ionic bond between potassium and bromine.

Based on the above reasoning, the pair that can form ionic bonds is:

- Potassium (K) and Bromine (Br)

Thus, the correct answer is:

E. Potassium (K) and Bromine (Br)