Answer :
To determine which vitamins Robert met at least 75% of his recommended daily allowance (RDA) for, we need to examine the nutrient content of his meal and compare it against 75% of his RDA for each vitamin.
First, let's summarize the nutrient values of his meal components:
- Salmon fillet (124 g):
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg\)[/tex]
- Boiled green beans (1 cup):
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg\)[/tex]
- Vitamin E: [tex]\(0.57 mg\)[/tex]
- Strawberries, sliced (1/2 cup):
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 mg\)[/tex]
- Vitamin E: [tex]\(0.42 mg\)[/tex]
Now let's calculate the total intake of each vitamin from the meal:
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg + 49.0 mg = 61.1 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg\)[/tex]
Next, we need to compute 75% of the RDA for each vitamin:
- 75% of RDA for Vitamin B12: [tex]\(0.75 \times 2.4 \mu g = 1.8 \mu g\)[/tex]
- 75% of RDA for Vitamin C: [tex]\(0.75 \times 75 mg = 56.25 mg\)[/tex]
- 75% of RDA for Vitamin E: [tex]\(0.75 \times 15 mg = 11.25 mg\)[/tex]
Finally, we compare Robert's intake against these values:
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex] which is greater than [tex]\(1.8 \mu g\)[/tex] (meets at least 75% of the RDA)
- Vitamin C: [tex]\(61.1 mg\)[/tex] which is greater than [tex]\(56.25 mg\)[/tex] (meets at least 75% of the RDA)
- Vitamin E: [tex]\(1.59 mg\)[/tex] which is less than [tex]\(11.25 mg\)[/tex] (does not meet at least 75% of the RDA)
Based on this analysis, Robert met at least 75% of his RDA for Vitamin B12 and Vitamin C, but not for Vitamin E.
Hence, the correct answer is:
B. Vitamin B12 and Vitamin C only
First, let's summarize the nutrient values of his meal components:
- Salmon fillet (124 g):
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg\)[/tex]
- Boiled green beans (1 cup):
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg\)[/tex]
- Vitamin E: [tex]\(0.57 mg\)[/tex]
- Strawberries, sliced (1/2 cup):
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 mg\)[/tex]
- Vitamin E: [tex]\(0.42 mg\)[/tex]
Now let's calculate the total intake of each vitamin from the meal:
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg + 49.0 mg = 61.1 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg\)[/tex]
Next, we need to compute 75% of the RDA for each vitamin:
- 75% of RDA for Vitamin B12: [tex]\(0.75 \times 2.4 \mu g = 1.8 \mu g\)[/tex]
- 75% of RDA for Vitamin C: [tex]\(0.75 \times 75 mg = 56.25 mg\)[/tex]
- 75% of RDA for Vitamin E: [tex]\(0.75 \times 15 mg = 11.25 mg\)[/tex]
Finally, we compare Robert's intake against these values:
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex] which is greater than [tex]\(1.8 \mu g\)[/tex] (meets at least 75% of the RDA)
- Vitamin C: [tex]\(61.1 mg\)[/tex] which is greater than [tex]\(56.25 mg\)[/tex] (meets at least 75% of the RDA)
- Vitamin E: [tex]\(1.59 mg\)[/tex] which is less than [tex]\(11.25 mg\)[/tex] (does not meet at least 75% of the RDA)
Based on this analysis, Robert met at least 75% of his RDA for Vitamin B12 and Vitamin C, but not for Vitamin E.
Hence, the correct answer is:
B. Vitamin B12 and Vitamin C only