Answered

Dichlorodifluoromethane [tex]$\left( CF_2Cl_2\right)$[/tex] is a chlorofluorocarbon (CFC) molecule that is used as a refrigerant. Scientists discovered that CFCs harm Earth's ozone [tex]$\left( O_3\right)$[/tex] layer, which protects us from the Sun's harmful ultraviolet (UV) rays. Another type of harmful CFC is [tex]$CHF_2Cl$[/tex], called chlorodifluoromethane.

The boiling point of [tex]$CHF_2Cl$[/tex] is about [tex]$-41^{\circ} C$[/tex]. The boiling point of [tex]$CF_2Cl_2$[/tex] is about [tex]$-30^{\circ} C$[/tex]. Using the multiple dropdown options, answer the following:

[tex]$CHF_2Cl$[/tex] has a [tex]$\square$[/tex] [Select] boiling point than [tex]$CF_2Cl_2$[/tex].

[tex]$CHF_2Cl$[/tex] has a [tex]$\square$[/tex] [Select] vapor pressure than [tex]$CF_2Cl_2$[/tex].

Thus, we can conclude that [tex]$CHF_2Cl$[/tex] has [tex]$\square$[/tex] [Select] intermolecular forces than [tex]$CF_2Cl_2$[/tex].



Answer :

GinnyAnswer
Let's analyze the question step-by-step based on the given boiling points:

1. Boiling Point Comparison:
- The boiling point of [tex]\( CHF_2Cl \)[/tex] is [tex]\( -41^{\circ} C \)[/tex].
- The boiling point of [tex]\( CF_2Cl_2 \)[/tex] is [tex]\( -30^{\circ} C \)[/tex].
- Since [tex]\( -41^{\circ} C \)[/tex] is lower than [tex]\( -30^{\circ} C \)[/tex], [tex]\( CHF_2Cl \)[/tex] has a lower boiling point than [tex]\( CF_2Cl_2 \)[/tex].

2. Vapor Pressure Relation:
- A substance with a lower boiling point has a higher vapor pressure at a given temperature.
- Therefore, [tex]\( CHF_2Cl \)[/tex] having a lower boiling point than [tex]\( CF_2Cl_2 \)[/tex] means [tex]\( CHF_2Cl \)[/tex] has a higher vapor pressure than [tex]\( CF_2Cl_2 \)[/tex].

3. Intermolecular Forces:
- Substances with higher vapor pressures have weaker intermolecular forces because their molecules escape the liquid phase more easily.
- Hence, [tex]\( CHF_2Cl \)[/tex] having a higher vapor pressure than [tex]\( CF_2Cl_2 \)[/tex] indicates that [tex]\( CHF_2Cl \)[/tex] has weaker intermolecular forces than [tex]\( CF_2Cl_2 \)[/tex].

The final step-by-step solution to fill in the blanks is:

- [tex]\( CHF_2Cl \)[/tex] has a lower boiling point than [tex]\( CF_2Cl_2 \)[/tex].
- [tex]\( CHF_2Cl \)[/tex] has a higher vapor pressure than [tex]\( CF_2Cl_2 \)[/tex].
- Thus, we can conclude that [tex]\( CHF_2Cl \)[/tex] has weaker intermolecular forces than [tex]\( CF_2Cl_2 \)[/tex].

Therefore, the filled in statements would be:

- [tex]\( CHF_2Cl \)[/tex] has a lower boiling point than [tex]\( CF_2Cl_2 \)[/tex].
- [tex]\( CHF_2Cl \)[/tex] has a higher vapor pressure than [tex]\( CF_2Cl_2 \)[/tex].
- Thus, we can conclude that [tex]\( CHF_2Cl \)[/tex] has weaker intermolecular forces than [tex]\( CF_2Cl_2 \)[/tex].