To determine which equation represents the total ionic equation for the reaction between nitric acid (HNO₃) and sodium hydroxide (NaOH), we need to look at how these compounds dissociate in aqueous solution and then determine the form of the total ionic equation.
1. Dissociation of HNO₃ and NaOH in aqueous solution:
- HNO₃ dissociates into H⁺ and NO₃⁻ ions.
- NaOH dissociates into Na⁺ and OH⁻ ions.
2. Writing the dissociation reactions:
- HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
- NaOH(aq) → Na⁺(aq) + OH⁻(aq)
3. Combining the ions to represent the reaction:
- Mixing the ions from HNO₃ and NaOH, we get: H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq).
4. Products of the reaction:
- When H⁺ and OH⁻ combine, they form water (H₂O).
- The remaining Na⁺ and NO₃⁻ ions remain in the aqueous solution.
- So, the complete reaction will be: HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l).
5. Writing the total ionic equation:
- We break all soluble reactants and products into their ionic forms:
- H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l).
6. Simplifying the ionic equation:
- We observe that Na⁺ and NO₃⁻ are spectator ions on both sides of the equation.
Thus, the final total ionic equation that represents the reaction is:
[tex]\[
H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) \longrightarrow Na⁺(aq) + NO₃⁻(aq) + H₂O(l)
\][/tex]
Comparing this with the given options, the correct choice is:
[tex]\[
H ^{+} + NO _3^{-} + Na ^{+} + OH ^{-} \longrightarrow Na ^{+} + NO _3^{-} + H _2 O
\][/tex]
So, the equation that represents the total ionic equation for the reaction of HNO₃ and NaOH is:
[tex]\[ \boxed{H ^{+} + NO _3^{-} + Na ^{+} + OH ^{-} \longrightarrow Na ^{+} + NO _3^{-} + H _2 O} \][/tex]
