The sides of an equilateral triangle are 8 units long. What is the length of the altitude of the triangle?

A. [tex]\(\frac{5}{2}\)[/tex] units
B. [tex]\(\frac{4}{5}\)[/tex] units
C. [tex]\(\frac{10}{2}\)[/tex] units
D. [tex]\(\frac{16}{5}\)[/tex] units



Answer :

To determine the length of the altitude of an equilateral triangle with side lengths of 8 units, follow these steps:

1. Identify the properties of an equilateral triangle:
An equilateral triangle has all three sides of equal length, and all three interior angles are 60 degrees.

2. Formula for the altitude of an equilateral triangle:
The altitude (height) of an equilateral triangle can be calculated using the formula:
[tex]\[ \text{altitude} = \frac{s \cdot \sqrt{3}}{2} \][/tex]
where [tex]\( s \)[/tex] is the length of a side.

3. Plug in the side length into the formula:
Given the side length [tex]\( s = 8 \)[/tex] units, substitute [tex]\( s \)[/tex] in the formula:
[tex]\[ \text{altitude} = \frac{8 \cdot \sqrt{3}}{2} \][/tex]

4. Simplify the expression:
Simplify the multiplication and division:
[tex]\[ \text{altitude} = 4 \cdot \sqrt{3} \][/tex]

5. Result:
Therefore, the altitude of the equilateral triangle with side lengths of 8 units is:
[tex]\[ 4 \cdot \sqrt{3} \approx 6.928203230275509 \][/tex]

The length of the altitude is approximately [tex]\( 6.928 \)[/tex] units. This number corresponds to the previously computed value using the given geometric properties and calculations.