Answer :
To solve the system of equations:
[tex]\[ \begin{array}{l} y = -5x + 3 \\ y = 1 \end{array} \][/tex]
we need to find the values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy both equations simultaneously. Here are the steps to solve this system:
1. Substitute the value of [tex]\(y\)[/tex] from the second equation into the first equation:
Given [tex]\( y = 1 \)[/tex] from the second equation, we can substitute this value into the first equation:
[tex]\[ 1 = -5x + 3 \][/tex]
2. Solve for [tex]\(x\)[/tex]:
Rearrange the equation to isolate [tex]\(x\)[/tex]:
[tex]\[ 1 = -5x + 3 \implies -5x = 1 - 3 \implies -5x = -2 \][/tex]
Divide both sides by [tex]\(-5\)[/tex]:
[tex]\[ x = \frac{-2}{-5} = 0.4 \][/tex]
3. Determine the corresponding [tex]\(y\)[/tex] value:
From the second equation [tex]\( y = 1 \)[/tex], we already know that when [tex]\(x = 0.4\)[/tex], [tex]\(y\)[/tex] will be 1.
Therefore, the solution to the system of equations is:
[tex]\[ (x, y) = (0.4, 1) \][/tex]
Among the given options, the correct one is:
[tex]\[ (0.4, 1) \][/tex]
[tex]\[ \begin{array}{l} y = -5x + 3 \\ y = 1 \end{array} \][/tex]
we need to find the values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy both equations simultaneously. Here are the steps to solve this system:
1. Substitute the value of [tex]\(y\)[/tex] from the second equation into the first equation:
Given [tex]\( y = 1 \)[/tex] from the second equation, we can substitute this value into the first equation:
[tex]\[ 1 = -5x + 3 \][/tex]
2. Solve for [tex]\(x\)[/tex]:
Rearrange the equation to isolate [tex]\(x\)[/tex]:
[tex]\[ 1 = -5x + 3 \implies -5x = 1 - 3 \implies -5x = -2 \][/tex]
Divide both sides by [tex]\(-5\)[/tex]:
[tex]\[ x = \frac{-2}{-5} = 0.4 \][/tex]
3. Determine the corresponding [tex]\(y\)[/tex] value:
From the second equation [tex]\( y = 1 \)[/tex], we already know that when [tex]\(x = 0.4\)[/tex], [tex]\(y\)[/tex] will be 1.
Therefore, the solution to the system of equations is:
[tex]\[ (x, y) = (0.4, 1) \][/tex]
Among the given options, the correct one is:
[tex]\[ (0.4, 1) \][/tex]