Answer :
First, let's identify the given values. We have a mean value of fluid ounces which is [tex]\(4.60 \times 10^3\)[/tex] fluid ounces. We also know that the uncertainty is expressed as a percentage of the mean value, which is 1%.
1. Convert the mean value into standard form for easier calculation.
The mean value [tex]\(4.60 \times 10^3\)[/tex] can be written as 4600 fluid ounces.
2. Identify the uncertainty percentage.
The uncertainty percentage is given as 1%.
3. Calculate the absolute uncertainty.
The absolute uncertainty is found by multiplying the mean value by the uncertainty percentage.
[tex]\[ \text{Uncertainty} = \text{Mean fluid ounces} \times \text{Uncertainty percentage} \][/tex]
Substituting the values:
[tex]\[ \text{Uncertainty} = 4600 \, \text{fluid ounces} \times 0.01 \][/tex]
4. Multiply to find the uncertainty value.
Performing the multiplication:
[tex]\[ \text{Uncertainty} = 4600 \times 0.01 = 46 \, \text{fluid ounces} \][/tex]
5. State the final mean value with its uncertainty.
The mean value of the fluid ounces is 4600 fluid ounces, and the uncertainty is 46 fluid ounces.
Therefore, the uncertainty of [tex]\(4.60 \times 10^3\)[/tex] fluid ounces is 46 fluid ounces.
1. Convert the mean value into standard form for easier calculation.
The mean value [tex]\(4.60 \times 10^3\)[/tex] can be written as 4600 fluid ounces.
2. Identify the uncertainty percentage.
The uncertainty percentage is given as 1%.
3. Calculate the absolute uncertainty.
The absolute uncertainty is found by multiplying the mean value by the uncertainty percentage.
[tex]\[ \text{Uncertainty} = \text{Mean fluid ounces} \times \text{Uncertainty percentage} \][/tex]
Substituting the values:
[tex]\[ \text{Uncertainty} = 4600 \, \text{fluid ounces} \times 0.01 \][/tex]
4. Multiply to find the uncertainty value.
Performing the multiplication:
[tex]\[ \text{Uncertainty} = 4600 \times 0.01 = 46 \, \text{fluid ounces} \][/tex]
5. State the final mean value with its uncertainty.
The mean value of the fluid ounces is 4600 fluid ounces, and the uncertainty is 46 fluid ounces.
Therefore, the uncertainty of [tex]\(4.60 \times 10^3\)[/tex] fluid ounces is 46 fluid ounces.