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In a genetics experiment on peas, one sample of offspring contained 379 green peas and 475 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of [tex]$\frac{3}{4}$[/tex] that was expected?

The probability of getting a green pea is approximately [tex]$\square$[/tex]
(Type an integer or decimal rounded to three decimal places as needed.)



Answer :

To solve this problem, follow these steps:

1. Determine the total number of peas observed:
- There are [tex]\(379\)[/tex] green peas and [tex]\(475\)[/tex] yellow peas.
- To find the total number of peas, add the number of green peas and yellow peas together:
[tex]\[ 379 + 475 = 854 \][/tex]
- So, the total number of peas is [tex]\(854\)[/tex].

2. Calculate the probability of getting a green pea:
- The probability is found by dividing the number of green peas by the total number of peas.
[tex]\[ \text{Probability of green pea} = \frac{\text{Number of green peas}}{\text{Total number of peas}} = \frac{379}{854} \][/tex]
- Performing this calculation, we get approximately [tex]\( \frac{379}{854} \approx 0.444 \)[/tex].

Hence, the probability of getting a green pea is approximately [tex]\(0.444\)[/tex].

Now, comparing this result to the expected probability of [tex]\(\frac{3}{4} \approx 0.75\)[/tex], we see that the observed probability ([tex]\(0.444\)[/tex]) is not particularly close to the expected probability ([tex]\(0.75\)[/tex]). This might suggest either a deviation due to random sampling variation or possibly some factor affecting the pea colors that wasn't accounted for in the initial expectation.

To conclude:
The probability of getting a green pea is approximately [tex]\(0.444\)[/tex].