Daniel and Jan agreed to pay [tex] \$559,000 [/tex] for a four-bedroom colonial home in Waltham, Massachusetts, with a [tex] \$70,000 [/tex] down payment. They have a 25-year mortgage at a fixed rate of [tex] 6 \frac{3}{8} \% [/tex]. (Use Table 15.1)

a. How much is their monthly payment?

Note: Round your answer to the nearest cent.

Monthly payment: [tex] \square [/tex]

b. After the first payment, what would be the balance of the principal?

Note: Round your answers to the nearest cent.

\begin{tabular}{|c|c|c|c|}
\hline
\multirow{2}{}{\text{Payment number}} & \multicolumn{2}{|c|}{\text{Portion to-}} & \multirow{2}{}{\text{Balance of loan outstanding}} \\
\cline{2-3} & \text{Interest} & \text{Principal} & \\
\hline 1 & & & \\
\hline
\end{tabular}



Answer :

Let's break down the process step by step to answer each part of the question.

### Part (a): Monthly Payment Calculation

1. Purchase Price and Down Payment:
- Purchase Price: \[tex]$559,000 - Down Payment: \$[/tex]70,000

2. Principal Loan Amount:
- The loan amount (principal) is calculated as:
[tex]\[ \text{Principal} = \text{Purchase Price} - \text{Down Payment} = \$559,000 - \$70,000 = \$489,000 \][/tex]

3. Annual Interest Rate:
- The annual interest rate is [tex]\(6\frac{3}{8}\%\)[/tex].
- Convert [tex]\(6\frac{3}{8}\%\)[/tex] to a decimal form:
[tex]\[ 6\frac{3}{8}\% = 6 + \frac{3}{8} = 6.375\% \][/tex]
- In decimal form, this is:
[tex]\[ 6.375\% = 0.06375 \][/tex]

4. Monthly Interest Rate:
- Convert the annual interest rate to a monthly interest rate by dividing by 12:
[tex]\[ \text{Monthly Interest Rate} = \frac{0.06375}{12} \approx 0.0053125 \][/tex]

5. Number of Payments:
- The mortgage duration is 25 years.
- Number of monthly payments is:
[tex]\[ \text{Number of Payments} = 25 \times 12 = 300 \][/tex]

6. Monthly Payment Calculation:
- Using the mortgage payment formula:
[tex]\[ M = P \times \frac{r(1 + r)^n}{(1 + r)^n - 1} \][/tex]
where:
- [tex]\(M\)[/tex] is the monthly payment
- [tex]\(P\)[/tex] is the principal loan amount (\[tex]$489,000) - \(r\) is the monthly interest rate (0.0053125) - \(n\) is the number of monthly payments (300) - Substituting the values: \[ M = 489000 \times \frac{0.0053125(1 + 0.0053125)^{300}}{(1 + 0.0053125)^{300} - 1} \] 7. Result: - The monthly payment is \$[/tex]3263.67.

So, the monthly payment is:
[tex]\[ \boxed{\$3263.67} \][/tex]

### Part (b): Balance After the First Payment

1. Interest and Principal Portions of the First Payment:
- The first interest portion is calculated as:
[tex]\[ \text{Interest Portion} = \text{Principal} \times \text{Monthly Interest Rate} = 489000 \times 0.0053125 = \$2597.8125 \][/tex]

- The principal portion of the first payment is:
[tex]\[ \text{Principal Portion} = \text{Monthly Payment} - \text{Interest Portion} = 3263.67 - 2597.8125 = \$665.8578253973474 \][/tex]

2. Balance After the First Payment:
- The remaining balance after the first payment is:
[tex]\[ \text{Balance After First Payment} = \text{Principal} - \text{Principal Portion} = 489000 - 665.8578253973474 = 488334.14 \][/tex]

Thus, after the first payment:

[tex]\[ \begin{array}{|c|c|c|c|} \hline \text{Payment number} & \text{Portion to Interest} & \text{Portion to Principal} & \text{Balance of loan outstanding} \\ \hline 1 & \$2597.81 & \$665.86 & \$488334.14 \\ \hline \end{array} \][/tex]

So, the balance of the principal after the first payment is:
[tex]\[ \boxed{\$488334.14} \][/tex]

Each value rounded to the nearest cent as needed.