Select the correct answer.

Robert is a 15-year-old boy. His recommended dietary intake for vitamins B12, C, and E is [tex]2.4 \mu g[/tex]/day, [tex]75 \text{ mg}[/tex]/day, and [tex]15 \text{ mg}[/tex]/day, respectively. He eats a salmon fillet with one cup of boiled green beans and half a cup of fresh sliced strawberries for lunch. If the nutrient values of his meal components are as shown below, for which vitamins did Robert meet at least [tex]75\%[/tex] of his recommended daily allowance?

\begin{tabular}{|l|l|l|l|}
\hline
& Vitamin B12 & Vitamin C & Vitamin E \\
\hline
salmon fillet [tex]$(124 g)$[/tex] & [tex]$5.87 \mu g$[/tex] & 0.0 mg & 0.60 mg \\
\hline
boiled green beans (1 cup) & [tex]$0.0 \mu g$[/tex] & 12.1 mg & 0.57 mg \\
\hline
strawberries, sliced [tex]$(1/2$[/tex] cup) & [tex]$0.0 \mu g$[/tex] & 49.0 mg & 0.42 mg \\
\hline
\end{tabular}

A. vitamin B12, vitamin C, and vitamin E
B. vitamin B12 and vitamin C only
C. vitamin B12 and vitamin E only
D. vitamin C and vitamin E only
E. vitamin B12 only



Answer :

Let's determine for which vitamins Robert meets at least 75% of his recommended daily allowance (RDA) based on his lunch consisting of a salmon fillet, boiled green beans, and sliced strawberries.

Given information:

- Robert's RDA:
- Vitamin B12: [tex]\(2.4 \, \mu g\)[/tex]
- Vitamin C: [tex]\(75 \, mg\)[/tex]
- Vitamin E: [tex]\(15 \, mg\)[/tex]

Nutrient values of the meal components:

- Salmon fillet:
- Vitamin B12: [tex]\(5.87 \, \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 \, mg\)[/tex]
- Vitamin E: [tex]\(0.60 \, mg\)[/tex]

- Boiled green beans (1 cup):
- Vitamin B12: [tex]\(0.0 \, \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 \, mg\)[/tex]
- Vitamin E: [tex]\(0.57 \, mg\)[/tex]

- Strawberries, sliced (1/2 cup):
- Vitamin B12: [tex]\(0.0 \, \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 \, mg\)[/tex]
- Vitamin E: [tex]\(0.42 \, mg\)[/tex]

Calculate total intake from the meal:

- Total Vitamin B12: [tex]\(5.87 \, \mu g + 0.0 \, \mu g + 0.0 \, \mu g = 5.87 \, \mu g\)[/tex]
- Total Vitamin C: [tex]\(0.0 \, mg + 12.1 \, mg + 49.0 \, mg = 61.1 \, mg\)[/tex]
- Total Vitamin E: [tex]\(0.60 \, mg + 0.57 \, mg + 0.42 \, mg = 1.59 \, mg\)[/tex]

Calculate the percentage of RDA met:

- Percentage of Vitamin B12: [tex]\(\frac{5.87 \, \mu g}{2.4 \, \mu g} \times 100 = 244.58 \%\)[/tex]
- Percentage of Vitamin C: [tex]\(\frac{61.1 \, mg}{75 \, mg} \times 100 = 81.47 \%\)[/tex]
- Percentage of Vitamin E: [tex]\(\frac{1.59 \, mg}{15 \, mg} \times 100 = 10.60 \%\)[/tex]

Determine which vitamins meet at least 75% of RDA:

- Vitamin B12: [tex]\(244.58 \% \geq 75\%\)[/tex]
- Vitamin C: [tex]\(81.47 \% \geq 75\%\)[/tex]
- Vitamin E: [tex]\(10.60 \% < 75\%\)[/tex]

Based on the calculations, Robert meets at least 75% of his RDA for Vitamins B12 and C only.

So, the correct answer is:

B. vitamin B12 and vitamin C only