Which expression is equivalent to the following complex fraction?

[tex]\[ \frac{\frac{-2}{x} + \frac{5}{y}}{\frac{3}{y} - \frac{2}{x}} \][/tex]

A. [tex]\(\frac{-2y + 5x}{3x - 2y}\)[/tex]

B. [tex]\(\frac{3x - 2y}{-2y + 5x}\)[/tex]

C. [tex]\(\frac{x^2 y^2}{(-2y + 5x)(3x - 2y)}\)[/tex]

D. [tex]\(\frac{(-2y + 5x)(3x - 2y)}{x^2 y^2}\)[/tex]



Answer :

To determine which expression is equivalent to the given complex fraction:

[tex]\[ \frac{\frac{-2}{x} + \frac{5}{y}}{\frac{3}{y} - \frac{2}{x}} \][/tex]

we need to simplify this complex fraction step-by-step.

1. Combine the numerators and denominators:
- For the numerator:
[tex]\[ \frac{-2}{x} + \frac{5}{y} \][/tex]
To combine these fractions, find a common denominator (which is [tex]\(xy\)[/tex]):
[tex]\[ \frac{-2y}{xy} + \frac{5x}{xy} = \frac{-2y + 5x}{xy} \][/tex]

- For the denominator:
[tex]\[ \frac{3}{y} - \frac{2}{x} \][/tex]
Again, find a common denominator (which is [tex]\(xy\)[/tex]):
[tex]\[ \frac{3x}{xy} - \frac{2y}{xy} = \frac{3x - 2y}{xy} \][/tex]

2. Write the complex fraction using the combined numerators and denominators:
[tex]\[ \frac{\frac{-2y + 5x}{xy}}{\frac{3x - 2y}{xy}} \][/tex]

3. Divide the numerators and denominators:
When dividing fractions, multiply by the reciprocal of the divisor:
[tex]\[ \frac{-2y + 5x}{xy} \div \frac{3x - 2y}{xy} = \frac{-2y + 5x}{xy} \cdot \frac{xy}{3x - 2y} = \frac{(-2y + 5x) \cdot xy}{xy \cdot (3x - 2y)} \][/tex]

4. Simplify the expression:
The [tex]\(xy\)[/tex] terms cancel out in the numerator and denominator:
[tex]\[ \frac{-2y + 5x}{3x - 2y} \][/tex]

Therefore, the simplified expression equivalent to the given complex fraction is:

[tex]\[ \frac{-2 y + 5 x}{3 x - 2 y} \][/tex]

Comparing this with the given choices, the equivalent expression is:

[tex]\[ \boxed{\frac{-2 y + 5 x}{3 x - 2 y}} \][/tex]