Answer :
To solve the system of equations using elimination, let's follow a step-by-step approach:
### Given System of Equations:
[tex]\[ \begin{array}{c} 3g + 4h = 24 \\ -g + 2h = 2 \end{array} \][/tex]
### Step 1: Eliminate One Variable
To eliminate the variable [tex]\( g \)[/tex], we will perform some operations on these equations. Let's start by eliminating [tex]\( g \)[/tex] from the second equation.
#### Adjust the Second Equation:
Multiply the entire second equation by 3 so that the coefficients of [tex]\( g \)[/tex] in both equations have the same magnitude but opposite signs:
[tex]\[ -3g + 6h = 6 \][/tex]
The system now becomes:
[tex]\[ \begin{array}{c} 3g + 4h = 24 \\ -3g + 6h = 6 \end{array} \][/tex]
### Step 2: Add the Equations to Eliminate [tex]\( g \)[/tex]
Add the two equations together:
[tex]\[ (3g + 4h) + (-3g + 6h) = 24 + 6 \][/tex]
[tex]\[ 3g - 3g + 4h + 6h = 30 \][/tex]
[tex]\[ 0g + 10h = 30 \][/tex]
So, the resulting equation is:
[tex]\[ 10h = 30 \][/tex]
### Step 3: Solve for [tex]\( h \)[/tex]
Divide both sides by 10:
[tex]\[ h = \frac{30}{10} = 3 \][/tex]
### Step 4: Substitute [tex]\( h \)[/tex] Back into One of the Original Equations
Now, we need to find the value of [tex]\( g \)[/tex]. Substitute [tex]\( h = 3 \)[/tex] into the second original equation [tex]\( -g + 2h = 2 \)[/tex]:
[tex]\[ -g + 2(3) = 2 \][/tex]
[tex]\[ -g + 6 = 2 \][/tex]
Subtract 6 from both sides:
[tex]\[ -g = 2 - 6 \][/tex]
[tex]\[ -g = -4 \][/tex]
Multiply both sides by -1:
[tex]\[ g = 4 \][/tex]
### Step 5: State the Solution
The solution to the system of equations is the ordered pair [tex]\( (g, h) \)[/tex]. Thus, in alphabetical order:
[tex]\[ (g, h) = (4, 3) \][/tex]
The correct answer is:
[tex]\[ (4, 3) \][/tex]
### Given System of Equations:
[tex]\[ \begin{array}{c} 3g + 4h = 24 \\ -g + 2h = 2 \end{array} \][/tex]
### Step 1: Eliminate One Variable
To eliminate the variable [tex]\( g \)[/tex], we will perform some operations on these equations. Let's start by eliminating [tex]\( g \)[/tex] from the second equation.
#### Adjust the Second Equation:
Multiply the entire second equation by 3 so that the coefficients of [tex]\( g \)[/tex] in both equations have the same magnitude but opposite signs:
[tex]\[ -3g + 6h = 6 \][/tex]
The system now becomes:
[tex]\[ \begin{array}{c} 3g + 4h = 24 \\ -3g + 6h = 6 \end{array} \][/tex]
### Step 2: Add the Equations to Eliminate [tex]\( g \)[/tex]
Add the two equations together:
[tex]\[ (3g + 4h) + (-3g + 6h) = 24 + 6 \][/tex]
[tex]\[ 3g - 3g + 4h + 6h = 30 \][/tex]
[tex]\[ 0g + 10h = 30 \][/tex]
So, the resulting equation is:
[tex]\[ 10h = 30 \][/tex]
### Step 3: Solve for [tex]\( h \)[/tex]
Divide both sides by 10:
[tex]\[ h = \frac{30}{10} = 3 \][/tex]
### Step 4: Substitute [tex]\( h \)[/tex] Back into One of the Original Equations
Now, we need to find the value of [tex]\( g \)[/tex]. Substitute [tex]\( h = 3 \)[/tex] into the second original equation [tex]\( -g + 2h = 2 \)[/tex]:
[tex]\[ -g + 2(3) = 2 \][/tex]
[tex]\[ -g + 6 = 2 \][/tex]
Subtract 6 from both sides:
[tex]\[ -g = 2 - 6 \][/tex]
[tex]\[ -g = -4 \][/tex]
Multiply both sides by -1:
[tex]\[ g = 4 \][/tex]
### Step 5: State the Solution
The solution to the system of equations is the ordered pair [tex]\( (g, h) \)[/tex]. Thus, in alphabetical order:
[tex]\[ (g, h) = (4, 3) \][/tex]
The correct answer is:
[tex]\[ (4, 3) \][/tex]