Graph the system of equations and identify the solution.

[tex]\[ 4x + 4y = -8 \][/tex]
[tex]\[ 2x + 2y = -4 \][/tex]

A. [tex]\((2, -4)\)[/tex]
B. [tex]\((0, -2)\)[/tex]
C. No Solution
D. Infinitely Many Solutions



Answer :

To determine the solution to the system of equations [tex]\(4x + 4y = -8\)[/tex] and [tex]\(2x + 2y = -4\)[/tex], we'll follow these steps:

1. Simplify the Equations:
- First equation: [tex]\(4x + 4y = -8\)[/tex]
- Second equation: [tex]\(2x + 2y = -4\)[/tex]

Step-by-Step Simplification:

Divide the first equation by 4:
[tex]\[ \frac{4x + 4y}{4} = \frac{-8}{4} \][/tex]
which simplifies to:
[tex]\[ x + y = -2 \][/tex]

Now divide the second equation by 2:
[tex]\[ \frac{2x + 2y}{2} = \frac{-4}{2} \][/tex]
which simplifies to:
[tex]\[ x + y = -2 \][/tex]

2. Conclusion:
We see that both simplified equations are identical, [tex]\(x + y = -2\)[/tex]. This tells us that the two original equations represent the same line.

3. Graphing:
To graph [tex]\(x + y = -2\)[/tex]:

- Find the y-intercept when [tex]\(x = 0\)[/tex]:
[tex]\[ 0 + y = -2 \implies y = -2 \quad \text{(Point: } (0, -2) \text{)} \][/tex]

- Find the x-intercept when [tex]\(y = 0\)[/tex]:
[tex]\[ x + 0 = -2 \implies x = -2 \quad \text{(Point: } (-2, 0) \text{)} \][/tex]

Plot these points on the graph and draw the line through them. Both [tex]\(4x + 4y = -8\)[/tex] and [tex]\(2x + 2y = -4\)[/tex] will graph to this same line.

4. Identify the Solution:
Since both equations describe the same line, they intersect at every point on that line. Therefore, they have infinitely many solutions.

Answer:
[tex]\[ \text{Infinitely Many Solutions} \][/tex]