You have found a store that is unique. All the shirts sell for a set price and all the pants are also priced the same in the entire store. You have purchased 3 shirts and 2 pants for [tex]$104.81, and your friend has purchased 2 shirts and one pant for $[/tex]61.33.

Set up and solve a system of linear equations. How much is one shirt?

A. [tex]$51.26
B. $[/tex]17.85
C. [tex]$25.63
D. $[/tex]43.48



Answer :

To determine the price of one shirt, we can set up and solve a system of linear equations based on the purchases described.

Step 1: Define the variables
Let's denote:
- [tex]\( s \)[/tex] as the price of one shirt
- [tex]\( p \)[/tex] as the price of one pant

Step 2: Create the equations
Based on the information given, we can write two equations:

1. For the scenario where 3 shirts and 2 pants cost [tex]$104.81: \[ 3s + 2p = 104.81 \] 2. For the scenario where 2 shirts and 1 pant cost $[/tex]61.33:
[tex]\[ 2s + p = 61.33 \][/tex]

Step 3: Solve the system of equations
We will solve these two equations simultaneously to find the values of [tex]\( s \)[/tex] and [tex]\( p \)[/tex].

First, solve the second equation [tex]\( 2s + p = 61.33 \)[/tex] for [tex]\( p \)[/tex]:
[tex]\[ p = 61.33 - 2s \][/tex]

Next, substitute [tex]\( p = 61.33 - 2s \)[/tex] into the first equation:
[tex]\[ 3s + 2(61.33 - 2s) = 104.81 \][/tex]

Simplify and solve for [tex]\( s \)[/tex]:
[tex]\[ 3s + 122.66 - 4s = 104.81 \][/tex]
[tex]\[ -s + 122.66 = 104.81 \][/tex]
[tex]\[ -s = 104.81 - 122.66 \][/tex]
[tex]\[ -s = -17.85 \][/tex]
[tex]\[ s = 17.85 \][/tex]

Therefore, the price of one shirt is:
[tex]\[ \boxed{17.85} \][/tex]