Martha wrote an example of a quadratic function for a homework assignment. The function she wrote is shown:

[tex] f(x)=5x^3+2x^2+7x-3 [/tex]

What possible changes can Martha make to correct her homework assignment? Select two options.

A. The first term, [tex] 5x^3 [/tex], can be eliminated.
B. The exponent on the first term, [tex] 5x^3 [/tex], can be changed to a 2 and then combined with the second term, [tex] 2x^2 [/tex].
C. The exponent on the second term, [tex] 2x^2 [/tex], can be changed to a 3 and then combined with the first term, [tex] 5x^3 [/tex].
D. The constant, -3, can be changed to a variable.
E. The [tex] 7x [/tex] can be eliminated.



Answer :

Certainly! Let’s guide Martha through correcting her homework assignment involving the function [tex]\( f(x) = 5x^3 + 2x^2 + 7x - 3 \)[/tex].

A quadratic function is in the form [tex]\( ax^2 + bx + c \)[/tex], where the highest power of [tex]\(x\)[/tex] is 2. The function she wrote includes a cubic term [tex]\( 5x^3 \)[/tex], which needs to be addressed to convert it into a proper quadratic function.

Here are the steps we need to follow to review the possible changes:

1. Elimination of the cubic term:
One way to convert the given function into a quadratic function is to eliminate the cubic term [tex]\( 5x^3 \)[/tex]. This means removing [tex]\( 5x^3 \)[/tex] entirely from the function:
[tex]\[ f(x) = 2x^2 + 7x - 3 \][/tex]
Now, this fits the form of a quadratic function.

2. Change the exponent of the cubic term and combine it with the quadratic term:
Another way to correct her function is to change the exponent of the cubic term [tex]\( 5x^3 \)[/tex] to 2. By doing this, we turn it into another quadratic term with the same variable exponent as the [tex]\( 2x^2 \)[/tex] term:
[tex]\[ 5x^2 + 2x^2 = 7x^2 \][/tex]
Thus, the new function becomes:
[tex]\[ f(x) = 7x^2 + 7x - 3 \][/tex]
Now this is also in the form of a quadratic function.

Therefore, the possible changes Martha can make to correct her homework assignment are:
1. The first term, [tex]\( 5x^3 \)[/tex], can be eliminated.
2. The exponent on the first term, [tex]\( 5x^3 \)[/tex], can be changed to a 2 and then combined with the second term, [tex]\( 2x^2 \)[/tex].

These two options are valid to convert her original function into a quadratic one. The other options mentioned do not result in a quadratic function and therefore are not appropriate corrections.