Complete the steps to factor [tex]56x^2 - 8x - 7x + 1[/tex] by grouping.

1. Group pairs of terms with common factors.
[tex]\[
(56x^2 - 8x) + (-7x + 1)
\][/tex]

2. Factor the GCF from each group.
[tex]\[
8x(7x - 1) - 1(7x - 1)
\][/tex]

3. Use the distributive property.

What is the factorization of the polynomial?
A. [tex](8x - 1)(7x - 1)[/tex]
B. [tex](8x + 1)(7x - 1)[/tex]
C. [tex](8x + 7x)(1 - 1)[/tex]



Answer :

To factor the given polynomial [tex]\( 56x^2 - 8x - 7x + 1 \)[/tex] by grouping, let's go through the detailed steps:

### Step 1: Group pairs of terms with common factors
Group the polynomial into two pairs of terms:
[tex]\[ (56x^2 - 8x) + (-7x + 1) \][/tex]

### Step 2: Factor the Greatest Common Factor (GCF) from each group

#### Group 1: [tex]\( 56x^2 - 8x \)[/tex]
Both terms have a common factor of [tex]\( 8x \)[/tex]:
[tex]\[ 56x^2 - 8x = 8x(7x - 1) \][/tex]

#### Group 2: [tex]\( -7x + 1 \)[/tex]
This group can be factored as:
[tex]\[ -7x + 1 = -1(7x - 1) \][/tex]

So, we now have:
[tex]\[ 8x(7x - 1) - 1(7x - 1) \][/tex]

### Step 3: Use the distributive property
Notice that both terms now contain the common binomial factor [tex]\( (7x - 1) \)[/tex]. We can factor out [tex]\( (7x - 1) \)[/tex]:
[tex]\[ 8x(7x - 1) - 1(7x - 1) = (8x - 1)(7x - 1) \][/tex]

Thus, the factorization of the polynomial [tex]\( 56x^2 - 8x - 7x + 1 \)[/tex] is:

[tex]\[ (8x - 1)(7x - 1) \][/tex]