A 10-foot board rests against a wall. The angle that the board makes with the ground is [tex]$60^{\circ}$[/tex]. How far is the base of the board away from the wall?

Select the correct trigonometric ratio and distance from the wall.

A. [tex]$\cos 60^{\circ}=\frac{10}{x}; x=20$[/tex] feet
B. [tex]$\cos 60^{\circ}=\frac{x}{10}; x=5$[/tex] feet
C. [tex]$\sin 60^{\circ}=\frac{x}{10}; x \approx 8.66$[/tex] feet
D. [tex]$\sin 60^{\circ}=\frac{10}{x}; x \approx 11.5$[/tex] feet



Answer :

To determine how far the base of the board is from the wall, we need to use the correct trigonometric ratio and solve for the distance.

Here is the detailed, step-by-step solution:

1. Identify the right triangle components:
- The board is the hypotenuse (10 feet).
- The distance from the wall to the base of the board is the adjacent side.
- The angle between the ground and the board is [tex]\(60^{\circ}\)[/tex].

2. Select the correct trigonometric function. In this case, the cosine function relates the adjacent side (distance from the wall) and the hypotenuse (the board):
[tex]\[ \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \][/tex]
For our scenario:
[tex]\[ \cos(60^{\circ}) = \frac{x}{10} \][/tex]
where [tex]\(x\)[/tex] is the distance we want to find.

3. Substitute [tex]\(\cos(60^{\circ})\)[/tex]. From trigonometric tables or known values:
[tex]\[ \cos(60^{\circ}) = \frac{1}{2} \][/tex]

4. Set up the equation:
[tex]\[ \frac{1}{2} = \frac{x}{10} \][/tex]

5. Solve for [tex]\(x\)[/tex]:
[tex]\[ x = 10 \times \frac{1}{2} = 5 \text{ feet} \][/tex]

Therefore, the distance from the base of the board to the wall is 5 feet.

The correct option is:
B. [tex]\(\cos 60^{\circ}=\frac{x}{10}; x=5\)[/tex] feet