Answer :
To determine the number of Carbon atoms in 0.2 moles of sodium carbonate (Na₂CO₃), follow these steps:
1. Identify the number of Carbon atoms per molecule of Na₂CO₃:
Sodium carbonate (Na₂CO₃) consists of two sodium (Na) atoms, one carbonate (CO₃) group, and given the CO₃ group consists of one Carbon (C) atom. Thus, each molecule of Na₂CO₃ contains 1 Carbon atom.
2. Determine Avogadro's Number:
Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms/mole. This is the number of entities (atoms, in this case) present in one mole of any substance.
3. Calculate the total number of Carbon atoms:
Since each molecule of Na₂CO₃ contains 1 Carbon atom, the number of Carbon atoms in 0.2 moles of Na₂CO₃ can be calculated as follows:
- Total Carbon atoms = (number of moles of Na₂CO₃) × (Avogadro's number) × (number of Carbon atoms per molecule).
Here:
```
Number of Carbon atoms = 0.2 moles × 6.02 × 10^{23} atoms/mole × 1 Carbon atom per molecule
```
Calculating this product:
```
Total Carbon atoms = 0.2 × 6.02 × 10^{23}
≈ 1.204 × 10^{23}
```
Therefore, the number of Carbon atoms in 0.2 moles of sodium carbonate (Na₂CO₃) is [tex]\(1.204 \times 10^{23}\)[/tex].
1. Identify the number of Carbon atoms per molecule of Na₂CO₃:
Sodium carbonate (Na₂CO₃) consists of two sodium (Na) atoms, one carbonate (CO₃) group, and given the CO₃ group consists of one Carbon (C) atom. Thus, each molecule of Na₂CO₃ contains 1 Carbon atom.
2. Determine Avogadro's Number:
Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms/mole. This is the number of entities (atoms, in this case) present in one mole of any substance.
3. Calculate the total number of Carbon atoms:
Since each molecule of Na₂CO₃ contains 1 Carbon atom, the number of Carbon atoms in 0.2 moles of Na₂CO₃ can be calculated as follows:
- Total Carbon atoms = (number of moles of Na₂CO₃) × (Avogadro's number) × (number of Carbon atoms per molecule).
Here:
```
Number of Carbon atoms = 0.2 moles × 6.02 × 10^{23} atoms/mole × 1 Carbon atom per molecule
```
Calculating this product:
```
Total Carbon atoms = 0.2 × 6.02 × 10^{23}
≈ 1.204 × 10^{23}
```
Therefore, the number of Carbon atoms in 0.2 moles of sodium carbonate (Na₂CO₃) is [tex]\(1.204 \times 10^{23}\)[/tex].