Cross a parent that is homozygous recessive for both traits (bbee) with a dihybrid (BbEe).

1. Draw a Punnett square in your notes.
2. For each offspring in the Punnett square, determine the phenotype (fur color and eye color).
3. Use that information to fill in the predicted fraction of each phenotype in the data table below.

[tex]\[
\begin{tabular}{|c|c|c|c|c|}
\hline
& \begin{tabular}{c}
Black \\
Fur and \\
Black \\
Eyes
\end{tabular}
& \begin{tabular}{c}
Black \\
Fur and \\
Red \\
Eyes
\end{tabular}
& \begin{tabular}{c}
White \\
Fur and \\
Black \\
Eyes
\end{tabular}
& \begin{tabular}{c}
White \\
Fur and \\
Red \\
Eyes
\end{tabular} \\
\hline
\begin{tabular}{c}
Predicted \\
Fraction
\end{tabular}
& & & & \\
\hline
\end{tabular}
\][/tex]



Answer :

To solve this problem, we will cross a parent that is homozygous recessive for both traits (bbee) with a dihybrid (BbEe). Here's a step-by-step explanation.

### 1. Identifying Possible Gametes

Parent 1 (bbee): Since this parent is homozygous recessive for both traits, the only possible gamete it can produce is be.

Parent 2 (BbEe): This parent is dihybrid (heterozygous for both traits), so it can produce four types of gametes:
- BE
- Be
- bE
- be

### 2. Constructing the Punnett Square

To construct the Punnett square, list the gametes from Parent 1 on one side (since it only has one type of gamete, it will be along one dimension), and the gametes from Parent 2 along the other side:

[tex]\[ \begin{array}{c|c|c|c|c} & BE & Be & bE & be \\ \hline be & BEbe & Bebe & bEbe & be \\ \end{array} \][/tex]

When we combine these gametes, we get the following offspring combinations:
- BEbe
- Bebe
- bEbe
- bebe

### 3. Determining the Phenotypes

To determine the phenotypes, we look at each allele combination:
1. BEbe:
- B (dominant black fur)
- E (dominant black eyes)
- Phenotype: Black Fur and Black Eyes

2. Bebe:
- B (dominant black fur)
- ee (recessive red eyes)
- Phenotype: Black Fur and Red Eyes

3. bEbe:
- bb (recessive white fur)
- E (dominant black eyes)
- Phenotype: White Fur and Black Eyes

4. bebe:
- bb (recessive white fur)
- ee (recessive red eyes)
- Phenotype: White Fur and Red Eyes

### 4. Counting and Predicting the Fractions

Let's count each phenotype:
- Black Fur and Black Eyes: 1
- Black Fur and Red Eyes: 1
- White Fur and Black Eyes: 1
- White Fur and Red Eyes: 1

Since there are a total of 4 offspring, the predicted fraction for each phenotype will be:

[tex]\[ \begin{array}{|c|c|c|c|c|} \hline & \text{Black Fur and Black Eyes} & \text{Black Fur and Red Eyes} & \text{White Fur and Black Eyes} & \text{White Fur and Red Eyes} \\ \hline \text{Predicted Fraction} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} \\ \hline \end{array} \][/tex]

So, the table will look like:

\begin{tabular}{|c|c|c|c|c|}
\hline & \begin{tabular}{c}
Black \\
Fur and \\
Black \\
Eyes
\end{tabular} & \begin{tabular}{c}
Black \\
Fur and \\
Red \\
Eyes
\end{tabular} & \begin{tabular}{c}
White \\
Fur and \\
Black \\
Eyes
\end{tabular} & \begin{tabular}{c}
White \\
Fur and \\
Red \\
Eyes
\end{tabular} \\
\hline \begin{tabular}{c}
Predicted \\
Fraction
\end{tabular} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} \\
\hline
\end{tabular}