Which methods could you use to calculate the [tex]\(y\)[/tex]-coordinate of the midpoint of a vertical line segment with endpoints at [tex]\((0,0)\)[/tex] and [tex]\((0,-12)\)[/tex]?

Check all that apply.
A. Divide [tex]\(-12\)[/tex] by 2.
B. Add the endpoints.
C. Count by hand.
D. Divide [tex]\(12\)[/tex] by 2.



Answer :

To determine the [tex]\( y \)[/tex]-coordinate of the midpoint of a vertical line segment with endpoints at [tex]\( (0,0) \)[/tex] and [tex]\( (0,-12) \)[/tex], we can analyze each method:

### A. Divide -12 by 2
This method is correct. The formula to find the [tex]\( y \)[/tex]-coordinate of the midpoint of a line segment with endpoints [tex]\((y_1)\)[/tex] and [tex]\((y_2)\)[/tex] is:

[tex]\[ y_{\text{midpoint}} = \frac{y_1 + y_2}{2} \][/tex]

Plugging in [tex]\( y_1 = 0 \)[/tex] and [tex]\( y_2 = -12 \)[/tex]:

[tex]\[ y_{\text{midpoint}} = \frac{0 + (-12)}{2} = \frac{-12}{2} = -6 \][/tex]

Therefore, dividing -12 by 2 gives the correct [tex]\( y \)[/tex]-coordinate.

### B. Add the endpoints
This method is incorrect. Adding the endpoints would give us [tex]\( 0 + (-12) = -12 \)[/tex], but this does not account for averaging the distance between the two points, which is required to find the midpoint.

### C. Count by hand
While theoretically possible, this method is not precise, practical, or recommended in a formal mathematical setting. Midpoint calculations require precise arithmetic, not manual counting.

### D. Divide 12 by 2
This method is incorrect. The correct calculation should consider the negative distance, as the segment goes from [tex]\( 0 \)[/tex] to [tex]\( -12 \)[/tex]. Dividing 12 by 2 disregards the negative sign, resulting in:

[tex]\[ \frac{12}{2} = 6 \][/tex]

This would incorrectly suggest that the midpoint is at [tex]\( y = 6 \)[/tex], which is not in the correct location on the line segment, as the actual midpoint is at [tex]\( y = -6 \)[/tex].

### Conclusion
The correct method to calculate the [tex]\( y \)[/tex]-coordinate of the midpoint is:

- A. Divide -12 by 2

Hence, the valid method is Method A, and the [tex]\( y \)[/tex]-coordinate obtained is [tex]\(-6.0\)[/tex].