Enter the data to create a histogram. Then select the correct answer.

\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|}
\hline
hours & 9 & 1 & 8 & 7 & 9 & 9 & 8 & 9 & 8 & 7 \\
\hline
\end{tabular}

A. The histogram is not symmetrical.
B. The histogram is symmetrical.
C. The data are evenly distributed.
D. The left side of the graph is the mirror image of the right side of the graph.



Answer :

To determine if the histogram of the given data is symmetrical, we'll first construct the histogram and then interpret its symmetry properties.

Here is a detailed, step-by-step solution:

1. Data Given: We start with the list of hours:
[tex]\[ [9, 1, 8, 7, 9, 9, 8, 9, 8, 7] \][/tex]

2. Constructing a Frequency Table:
We count the occurrences of each value in the list.
[tex]\[ \begin{array}{|c|c|} \hline \text{Hours} & \text{Frequency} \\ \hline 1 & 1 \\ 7 & 2 \\ 8 & 3 \\ 9 & 4 \\ \hline \end{array} \][/tex]

3. Creating the Histogram:
To create the histogram, we plot the frequencies of hours on the y-axis against the hours on the x-axis.

4. Visual Analysis of Symmetry:
To check if a histogram is symmetrical, we need to visually assess if the shape of the histogram on the left side is a mirror image of the shape on the right side. Here's a rough sketch based on the frequency table:
```
Frequency
4 |
3 |
2 |

1 |

0 |_________________
1 7 8 9 (hours)
```

5. Symmetry Check:
- A histogram is symmetrical if both sides of its central point are mirror images of each other. Here, the central point can be considered around values 7.5 to 8.5.
- From the histogram, we observe that the left side consists of hours 1, 7, which have fewer occurrences compared to the right side (which is heavily weighted towards hours 8 and 9). Therefore, the left side doesn't mirror the right side.

6. Final Conclusion:
Given the above observations:
- The histogram is not symmetrical because the distribution of values (especially at hours 8 and 9) is not balanced or mirrored on the opposite side.

Thus, the correct answer is:

The histogram is not symmetrical.