To solve the system of equations below, Kira isolated the variable [tex]\( y \)[/tex] in the first equation and then substituted it into the second equation. What was the resulting equation?

[tex]\[
\begin{cases}
3y = 12x \\
x^2 + y^2 = 81
\end{cases}
\][/tex]

A. [tex]\( x^2 + 16x^2 = 81 \)[/tex]
B. [tex]\( x^2 + 16x = 81 \)[/tex]
C. [tex]\( x^2 + 4x = 81 \)[/tex]
D. [tex]\( x^2 + 4x^2 = 81 \)[/tex]



Answer :

Let's solve the system of equations step by step to find the resulting equation that Kira obtained.

Given the system of equations:

1) [tex]\( 3y = 12x \)[/tex]
2) [tex]\( x^2 + y^2 = 81 \)[/tex]

1. Isolate [tex]\( y \)[/tex] in the first equation:

Starting with the first equation:
[tex]\[ 3y = 12x \][/tex]

Divide both sides by 3 to solve for [tex]\( y \)[/tex]:
[tex]\[ y = \frac{12x}{3} \][/tex]
[tex]\[ y = 4x \][/tex]

2. Substitute [tex]\( y \)[/tex] into the second equation:

Now substitute [tex]\( y = 4x \)[/tex] into the second equation:
[tex]\[ x^2 + y^2 = 81 \][/tex]

Replace [tex]\( y \)[/tex] with [tex]\( 4x \)[/tex]:
[tex]\[ x^2 + (4x)^2 = 81 \][/tex]

Simplify the equation:
[tex]\[ x^2 + 16x^2 = 81 \][/tex]

Combine like terms:
[tex]\[ 17x^2 = 81 \][/tex]

However, before combining like terms, the resulting equation prior to simplification is:
[tex]\[ x^2 + 16x^2 = 81 \][/tex]

Therefore, the resulting equation that Kira obtained is [tex]\(x^2 + 16x^2 = 81\)[/tex].

So, the correct answer is:
A. [tex]\( x^2 + 16x^2 = 81 \)[/tex]