The perimeter [tex]P[/tex] of a rectangle is [tex]P = 2l + 2w[/tex], where [tex]l[/tex] and [tex]w[/tex] are the rectangle's length and width, respectively.

(a) Rewrite the formula to find the length given the perimeter and width. Justify each step in your solution with the property used.



Answer :

To solve for the length [tex]\( l \)[/tex] in terms of the perimeter [tex]\( P \)[/tex] and the width [tex]\( w \)[/tex] of a rectangle, we can manipulate the formula [tex]\( P = 2l + 2w \)[/tex] using algebraic properties. Here’s the step-by-step process:

1. Start with the given formula:
[tex]\[ P = 2l + 2w \][/tex]
This equation represents the perimeter of a rectangle in terms of its length and width.

2. Subtract [tex]\( 2w \)[/tex] from both sides:
[tex]\[ P - 2w = 2l \][/tex]
Justification: Using the property of equality (what you do to one side of the equation, you must do to the other) to isolate the term involving [tex]\( l \)[/tex].

3. Divide both sides by 2:
[tex]\[ \frac{P - 2w}{2} = l \][/tex]
Justification: Using the division property of equality to solve for [tex]\( l \)[/tex]. Dividing both sides by 2 simplifies the equation.

4. Write the final solution:
[tex]\[ l = \frac{P - 2w}{2} \][/tex]

So, the length [tex]\( l \)[/tex] is given by the formula [tex]\(\frac{P - 2w}{2}\)[/tex] when you know the perimeter [tex]\( P \)[/tex] and the width [tex]\( w \)[/tex] of the rectangle.