Drill Problem 12-6 (Algo) [LU 12-1 (3)]

Calculate what [tex]\$730[/tex] would grow to at [tex]5\%[/tex] per year compounded daily for 7 years. (Use Table 12.2)

Note: Round your final answer to the nearest cent.

Amount: $\square$



Answer :

To find out how much \[tex]$730 will grow to at an interest rate of 5% per year, compounded daily for 7 years, we will use the formula for compound interest. Here are the steps you need to follow: 1. Identify the variables in the compound interest formula: - Principal (\(P\)): \$[/tex]730
- Annual interest rate ([tex]\(r\)[/tex]): 5%, or 0.05 in decimal form
- Number of times the interest is compounded per year ([tex]\(n\)[/tex]): 365 (daily)
- Number of years ([tex]\(t\)[/tex]): 7

2. Write down the compound interest formula:
[tex]\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \][/tex]
Here, [tex]\(A\)[/tex] is the amount of money accumulated after n years, including interest.

3. Substitute the variables into the compound interest formula:

[tex]\[ A = 730 \left(1 + \frac{0.05}{365}\right)^{365 \times 7} \][/tex]

4. Calculate the exponent:

[tex]\[ 365 \times 7 = 2555 \][/tex]

5. Calculate the rate divided by the number of times interest is compounded:

[tex]\[ \frac{0.05}{365} = 0.0001369863 \approx 0.000137 \][/tex]

6. Add 1 to the fraction:

[tex]\[ 1 + 0.000137 = 1.000137 \][/tex]

7. Raise 1.000137 to the power of 2555:

[tex]\[ 1.000137^{2555} \approx 1.41958 \][/tex]

8. Multiply the principal by this result:

[tex]\[ A = 730 \times 1.41958 \approx 1035.8944793561636 \][/tex]

9. Round the final amount to the nearest cent:

[tex]\[ A \approx 1035.89 \][/tex]

So, \[tex]$730 will grow to \$[/tex]1035.89 after 7 years at an annual interest rate of 5% compounded daily.