Solve [tex]$v^3=-17$[/tex] where [tex]$v$[/tex] is a real number. Simplify your answer as much as possible.

(If there is more than one solution, separate them with commas.)

[tex]v = \sqrt[\square]{\square}[/tex]

[tex]\boxed{\text{No solution}}[/tex]



Answer :

To solve the equation [tex]\( v^3 = -17 \)[/tex], we need to find the value of [tex]\( v \)[/tex] such that when [tex]\( v \)[/tex] is cubed, the result is [tex]\(-17\)[/tex].

Let's start by isolating [tex]\( v \)[/tex].

First, we want to express [tex]\( v \)[/tex] in terms of [tex]\(-17\)[/tex]:

[tex]\[ v = (-17)^{1/3} \][/tex]

This expression [tex]\( (-17)^{1/3} \)[/tex] represents the cube root of [tex]\(-17\)[/tex]. We want to determine what [tex]\( v \)[/tex] is when taking the cube root of [tex]\(-17\)[/tex].

It's important to note that the cube root of a negative number can involve complex numbers, since real numbers only. In the context of complex numbers, we find:

[tex]\[ v = (1.2856407953291178 + 2.2267951777932917i) \][/tex]

This solution is complex, meaning there is no real solution to the equation [tex]\( v^3 = -17 \)[/tex]. Therefore, we conclude:

[tex]\[ v = \text{No solution} \][/tex]