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Complete the synthetic division to find the quotient of [tex][tex]$3x^3 - 25x^2 + 12x - 32$[/tex][/tex] and [tex]$x - 8$[/tex].



Answer :

To perform synthetic division for the polynomial [tex]$3x^3 - 25x^2 + 12x - 32$[/tex] by the divisor [tex]$x - 8$[/tex], follow these steps:

1. Identify the root of the divisor [tex]$x - 8$[/tex], which is [tex]$8$[/tex].
2. Write down the coefficients of the polynomial: [tex]$3, -25, 12, -32$[/tex].
3. Start with the leading coefficient, [tex]$3$[/tex], and bring it down.

Now, proceed with the synthetic division process step by step:

[tex]\[ \begin{array}{r|rrrr} 8 & 3 & -25 & 12 & -32 \\ & & & & \\ \hline & 3 & & & \\ \end{array} \][/tex]

4. Multiply the value just written down by the root [tex]$8$[/tex] and write the result under the next coefficient.

[tex]\[ \begin{array}{r|rrrr} 8 & 3 & -25 & 12 & -32 \\ & & 24 & & \\ \hline & 3 & & & \\ \end{array} \][/tex]

5. Add the column: [tex]$-25 + 24 = -1$[/tex]. Write this result in the bottom row.

[tex]\[ \begin{array}{r|rrrr} 8 & 3 & -25 & 12 & -32 \\ & & 24 & & \\ \hline & 3 & -1 & & \\ \end{array} \][/tex]

6. Repeat the process: Multiply [tex]$-1$[/tex] by [tex]$8$[/tex] (write [tex]$-8$[/tex] under the next coefficient), then add the column.

[tex]\[ \begin{array}{r|rrrr} 8 & 3 & -25 & 12 & -32 \\ & & 24 & -8 & \\ \hline & 3 & -1 & 4 & \\ \end{array} \][/tex]

7. Continue: Multiply [tex]$4$[/tex] by [tex]$8$[/tex] (write [tex]$32$[/tex] under the last coefficient), then add the column.

[tex]\[ \begin{array}{r|rrrr} 8 & 3 & -25 & 12 & -32 \\ & & 24 & -8 & 32 \\ \hline & 3 & -1 & 4 & 0 \\ \end{array} \][/tex]

8. The final row gives the coefficients of the quotient polynomial and the remainder. The quotient is [tex]$3x^2 - x + 4$[/tex], and the remainder is [tex]$0$[/tex].

Thus, the quotient of the division of [tex]$3x^3 - 25x^2 + 12x - 32$[/tex] by [tex]$x - 8$[/tex] is [tex]$3x^2 - x + 4$[/tex], and the remainder is [tex]$0$[/tex].