Question 5:
How would you complete the print function so that it returns "read"?

[tex]\[
\begin{array}{l}
\text{my\_string = "I'm ready"} \\
\text{print(...)}
\end{array}
\][/tex]

A. my\_string [tex]\([4:7]\)[/tex]
B. my\_string [tex]\([5:9]\)[/tex]
C. my\_string [tex]\([5:4]\)[/tex]
D. my\_string [tex]\([4:8]\)[/tex]



Answer :

To determine the correct slicing indices that will result in the substring "read" from the given string `my_string = "I'm ready"`, we need to understand how string slicing works in Python.

String slicing uses the syntax `my_string[start:end]`, where `start` is the beginning index (inclusive) and `end` is the ending index (exclusive).

Given the string `my_string = "I'm ready"`:

1. Determine the correct indices:

- The string "I'm ready" has the following positions:
```
I ' m r e a d y
0 1 2 3 4 5 6 7 8
```

2. Find the indices for "read":
- The substring "read" starts at index 4 (`r`) and ends at index 8 (`y` is at index 8, but it is exclusive, so we do not include it).

3. Verify the slicing index:
- Slicing from index 4 up to but not including index 8 should give us "read".
- Hence the correct slicing of the string would be `my_string[4:8]`.

4. Test the other options to confirm their correctness:
- `my_string[4:7]` results in "rea", missing the 'd'.
- `my_string[5:9]` results in "eady", including the 'y'.
- `my_string[5:4]` is invalid as the start index is greater than the end index.

Therefore, the print function should use the slicing `my_string[4:8]` to return "read".

Hence, the correct completion is:
```print(my_string[4:8])```

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