What is the point-slope form of a line with slope [tex]\frac{3}{2}[/tex] that contains the point [tex](-1,2)[/tex]?

A. [tex]y - 2 = \frac{3}{2}(x + 1)[/tex]
B. [tex]y - 2 = \frac{3}{2}(x - 1)[/tex]
C. [tex]y + 2 = \frac{3}{2}(x - 1)[/tex]
D. [tex]y + 2 = \frac{3}{2}(x + 1)[/tex]



Answer :

To find the point-slope form of a line with a given slope and a specific point that lies on the line, follow these steps:

1. Identify the components:
- Slope (m): The slope of the line is given as [tex]\(\frac{3}{2}\)[/tex].
- Point (x₁, y₁): The given point through which the line passes is [tex]\((-1, 2)\)[/tex].

2. Point-Slope Form Equation:
The point-slope form of the equation of a line is given by:
[tex]\[ y - y_1 = m(x - x_1) \][/tex]
where [tex]\( m \)[/tex] is the slope, and [tex]\((x_1, y_1)\)[/tex] is the point on the line.

3. Substitute the given values into the equation:
- Here, [tex]\( m = \frac{3}{2} \)[/tex]
- And the point is [tex]\((x_1, y_1) = (-1, 2)\)[/tex]

4. Implement the substitution into the point-slope form:
[tex]\[ y - 2 = \frac{3}{2}(x - (-1)) \][/tex]

5. Simplify the expression:
- The term [tex]\( x - (-1) \)[/tex] simplifies to [tex]\( x + 1 \)[/tex]:
[tex]\[ y - 2 = \frac{3}{2}(x + 1) \][/tex]

Therefore, the point-slope form of the line with slope [tex]\(\frac{3}{2}\)[/tex] that passes through the point [tex]\((-1, 2)\)[/tex] is:

A. [tex]\( y - 2 = \frac{3}{2}(x + 1) \)[/tex]

Answer:

A. y - 2 = (3/2)(x + 1)

Step-by-step explanation:

The point slope form of a line is given by

y - y1 = m(x-x1)  where m is the slope of a line and ( x1,y1) is a point on the line.

Given the slope 3/2  and a point (-1,2)

y-2 = 3/2(x- -1)

y-2 = 3/2(x+1)