What is the interest earned after 1 year in a savings account with an initial investment of [tex]\$ 1,550[/tex] and a [tex]4.2\%[/tex] simple interest rate?

\[
\text{Interest} = \$[?]
\]



Answer :

To find the interest earned after 1 year in a savings account with an initial investment of \[tex]$1,550 at a 4.2% simple interest rate, we use the simple interest formula: \[ \text{Interest} = P \times r \times t \] where: - \(P\) is the principal amount (initial investment), - \(r\) is the annual interest rate (expressed as a decimal), - \(t\) is the time in years. Given: \[ P = 1550 \quad \text{(initial investment)} \] \[ r = 4.2\% = 0.042 \quad \text{(interest rate in decimal form)} \] \[ t = 1 \quad \text{(time period in years)} \] Now, substitute the given values into the formula: \[ \text{Interest} = 1550 \times 0.042 \times 1 \] Perform the multiplication: \[ \text{Interest} = 65.10000000000001 \] Hence, the interest earned after 1 year is: \[ \text{Interest} = \$[/tex]65.10
\]