What is the interest earned after 1 year in a savings account with an initial investment of [tex]\$1750[/tex] and a [tex]2\%[/tex] simple interest rate?

[tex]\text{Interest} = \$[?][/tex]



Answer :

To find the interest earned after 1 year in a savings account with an initial investment of [tex]$1750 and a 2% simple interest rate, we can use the simple interest formula: \[ \text{Interest} = P \times r \times t \] where: - \(P\) is the principal or initial investment, - \(r\) is the annual interest rate (expressed as a decimal), - \(t\) is the time period in years. In this case, the initial investment \(P\) is $[/tex]1750, the annual interest rate [tex]\(r\)[/tex] is 2%, or 0.02 as a decimal, and the time period [tex]\(t\)[/tex] is 1 year.

Plugging in these values, we get:
[tex]\[ \text{Interest} = 1750 \times 0.02 \times 1 \][/tex]

Performing the multiplication:
[tex]\[ \text{Interest} = 35.0 \][/tex]

Therefore, the interest earned after 1 year is:
[tex]\[ \text{Interest} = \$35.0 \][/tex]