What is the balance after 1 year in a savings account with an initial investment of [tex]\$1750[/tex] and a [tex]2\%[/tex] simple interest rate?

\[
\begin{array}{r}
\text{Interest} = \$35.00 \\
\text{Balance} = \$[?]
\end{array}
\]



Answer :

To determine the balance after 1 year for a savings account with an initial investment of [tex]$1750 and a 2% simple interest rate, we can follow these steps: 1. Calculate the interest earned: - The formula for simple interest is: \[ \text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time} \] - Here, the principal (initial investment) is $[/tex]1750, the rate is 2% (which is 0.02 as a decimal), and the time is 1 year.
- Plugging in these values:
[tex]\[ \text{Interest} = 1750 \times 0.02 \times 1 = 35.00 \][/tex]

2. Determine the final balance:
- The final balance is the sum of the initial investment and the interest earned.
- Therefore:
[tex]\[ \text{Final Balance} = \text{Principal} + \text{Interest} = 1750 + 35 = 1785.00 \][/tex]

Thus, the interest earned after 1 year is [tex]$35.00, and the balance after 1 year in the savings account is: \[ \text{Balance} = \$[/tex]1785.00
\]