The mean ages with standard deviations of four swim teams at a swim club are given below.

\begin{tabular}{|c|c|c|}
\hline
Team & Mean & Standard Deviation \\
\hline
Stars & 16 & 4.1 \\
\hline
Dolphins & 18 & 1.5 \\
\hline
Giants & 14 & 0.3 \\
\hline
Mackerels & 15 & 2.3 \\
\hline
\end{tabular}

Which statement is most likely to be true?

A. The ages of the Mackerels are the most dispersed from the team's mean.

B. The ages of the Stars are the most dispersed from the team's mean.

C. The ages of the Dolphins are the most dispersed from the team's mean.

D. The ages of the Giants are the most dispersed from the team's mean.



Answer :

Here is a step-by-step solution for determining which statement is most likely to be true based on the ages and standard deviations of the four swim teams:

1. Understand the concept:
Standard deviation is a measure of the amount of variation or dispersion in a set of values. A higher standard deviation indicates that the values are spread out over a wider range.

2. Given data:
- Stars: Mean = 16, Standard Deviation = 4.1
- Dolphins: Mean = 18, Standard Deviation = 1.5
- Giants: Mean = 14, Standard Deviation = 0.3
- Mackerels: Mean = 15, Standard Deviation = 2.3

3. Comparison of standard deviations:
To determine which team has the most dispersed ages from the mean, compare the standard deviation values for each team:
- Stars: Standard Deviation = 4.1
- Dolphins: Standard Deviation = 1.5
- Giants: Standard Deviation = 0.3
- Mackerels: Standard Deviation = 2.3

4. Identify the largest standard deviation:
The largest standard deviation among the given teams is 4.1.

5. Conclusion:
The team with the largest standard deviation is the Stars. Therefore, the statement most likely to be true is:

"The ages of the Stars are the most dispersed from the team's mean."