If the total sum of each row and column is the same, find the sum.

\begin{tabular}{l|l|l}
[tex]$10 + (-5)$[/tex] & [tex]$-6 + (-9)$[/tex] & [tex]$-1 + 12$[/tex] \\
\hline
[tex]$-9 + 13$[/tex] & [tex]$-2 + (-7)$[/tex] & [tex]$11 + (-3)$[/tex] \\
\hline
[tex]$-5 + 25$[/tex] & [tex]$\underbrace{-4 + (-4)}_{-8}$[/tex] & [tex]$21 + (-9)$[/tex]
\end{tabular}

LEE'S SUM: [tex]$\quad$[/tex]



Answer :

Let's examine the given grid and provided values step-by-step:

First, let's resolve each value in the grid:
[tex]\[ \begin{array}{|c|c|c|} \hline 10 + (-5) & -6 + (-9) & -1 + 12 \\ \hline -9 + 13 & -2 + (-7) & 11 + (-3) \\ \hline -5 + 25 & -4 + (-4) & 21 + (-9) \\ \hline \end{array} \][/tex]

Now let's compute each expression:
- [tex]\(10 + (-5) = 5\)[/tex]
- [tex]\(-6 + (-9) = -15\)[/tex]
- [tex]\(-1 + 12 = 11\)[/tex]
- [tex]\(-9 + 13 = 4\)[/tex]
- [tex]\(-2 + (-7) = -9\)[/tex]
- [tex]\(11 + (-3) = 8\)[/tex]
- [tex]\(-5 + 25 = 20\)[/tex]
- [tex]\(-4 + (-4) = -8\)[/tex]
- [tex]\(21 + (-9) = 12\)[/tex]

Replacing these values into the grid, we get:
[tex]\[ \begin{array}{|c|c|c|} \hline 5 & -15 & 11 \\ \hline 4 & -9 & 8 \\ \hline 20 & -8 & 12 \\ \hline \end{array} \][/tex]

Next, calculate the sum of each row:
- First row: [tex]\(5 + (-15) + 11 = 1\)[/tex]
- Second row: [tex]\(4 + (-9) + 8 = 3\)[/tex]
- Third row: [tex]\(20 + (-8) + 12 = 24\)[/tex]

Let’s list these row sums:
[tex]\[ [1, 3, 24] \][/tex]

Finally, calculate the overall sum of the grid:
[tex]\[ 1 + 3 + 24 = 28 \][/tex]

Therefore, the row sums are [tex]\( [1, 3, 24] \)[/tex], and the overall sum of the grid is [tex]\( 28 \)[/tex].