Question 2 of 25

Which of the following is an equation of a line perpendicular to the equation [tex]$y = -\frac{2}{3} x - 4$[/tex]?

A. [tex]$y = -\frac{2}{3} x + 1$[/tex]
B. [tex][tex]$y = \frac{2}{3} x + 1$[/tex][/tex]
C. [tex]$y = -\frac{3}{2} x + 1$[/tex]
D. [tex]$y = \frac{3}{2} x + 1$[/tex]



Answer :

To determine which equation represents a line that is perpendicular to the given equation [tex]\( y = -\frac{2}{3} x - 4 \)[/tex], we need to understand the relationship between the slopes of perpendicular lines.

### Step-by-Step Solution:

1. Identify the Slope of the Given Line:

The equation of the line is provided in the slope-intercept form, [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope and [tex]\( b \)[/tex] is the y-intercept. For the equation [tex]\( y = -\frac{2}{3} x - 4 \)[/tex], the slope [tex]\( m \)[/tex] is [tex]\( -\frac{2}{3} \)[/tex].

2. Determine the Slope of the Perpendicular Line:

The slopes of two perpendicular lines multiply to -1. In other words, if [tex]\( m_1 \)[/tex] is the slope of one line, and [tex]\( m_2 \)[/tex] is the slope of the line perpendicular to it, then [tex]\( m_1 \times m_2 = -1 \)[/tex].

Given [tex]\( m_1 = -\frac{2}{3} \)[/tex], we need to find [tex]\( m_2 \)[/tex] such that:

[tex]\[ -\frac{2}{3} \times m_2 = -1 \][/tex]

Solving for [tex]\( m_2 \)[/tex]:

[tex]\[ m_2 = \frac{3}{2} \][/tex]

3. Find the Correct Equation:

The slope of the line perpendicular to the given line is [tex]\( \frac{3}{2} \)[/tex]. Now, looking at the provided options:

A. [tex]\( y = -\frac{2}{3} x + 1 \)[/tex] (Slope: [tex]\(-\frac{2}{3}\)[/tex])
B. [tex]\( y = \frac{2}{3} x + 1 \)[/tex] (Slope: [tex]\(\frac{2}{3}\)[/tex])
C. [tex]\( y = -\frac{3}{2} x + 1 \)[/tex] (Slope: [tex]\(-\frac{3}{2}\)[/tex])
D. [tex]\( y = \frac{3}{2} x + 1 \)[/tex] (Slope: [tex]\(\frac{3}{2}\)[/tex])

The correct choice has to have a slope of [tex]\( \frac{3}{2} \)[/tex].

Therefore, the correct answer is:

D. [tex]\( y = \frac{3}{2} x + 1 \)[/tex]