Instructions: Use the given information to answer the questions and interpret key features. Use any method of graphing or solving. Round to one decimal place, if necessary.

The trajectory of a golf ball in a chip from the rough has a parabolic pattern. The height, in feet, of the ball is given by the equation [tex]h(x)=-0.25x^2+3.4x[/tex], where [tex]x[/tex] is the number of feet away from the golf club (along the ground) the ball is.

1. The ball starts [tex]\square[/tex] feet above the ground.
2. The ball reaches a maximum height of [tex]\square[/tex] feet at a horizontal distance of [tex]\square[/tex] feet away from the golf club it was hit with.
3. The ball returns to the ground at about [tex]\square[/tex] feet away.



Answer :

Let's analyze the given parabolic equation for the height of the golf ball: [tex]\( h(x) = -0.25x^2 + 3.4x \)[/tex], where [tex]\( x \)[/tex] represents the horizontal distance from the golf club in feet, and [tex]\( h(x) \)[/tex] represents the height of the ball in feet.

1. Initial Height:
The initial height of the ball can be determined by evaluating the height equation when [tex]\( x = 0 \)[/tex] (right at the moment when the ball starts from the ground).

[tex]\[ h(0) = -0.25(0)^2 + 3.4(0) = 0 \][/tex]

Thus, the ball starts 0 feet above the ground.

2. Maximum Height and Horizontal Distance:
The maximum height of the ball can be found by determining the vertex of the parabola. For the given quadratic equation [tex]\( h(x) = -0.25x^2 + 3.4x \)[/tex], the vertex form is used by finding the value of [tex]\( x \)[/tex] at the vertex:

[tex]\[ x_{\text{vertex}} = -\frac{b}{2a} \][/tex]

Here, [tex]\( a = -0.25 \)[/tex] and [tex]\( b = 3.4 \)[/tex]. Thus,

[tex]\[ x_{\text{vertex}} = -\frac{3.4}{2(-0.25)} = 6.8 \][/tex]

Plugging [tex]\( x_{\text{vertex}} \)[/tex] back into the height equation to find the maximum height:

[tex]\[ h(6.8) = -0.25(6.8)^2 + 3.4(6.8) = 11.56 \text{ feet} \][/tex]

Thus, the ball reaches a maximum height of 11.6 feet at a horizontal distance of 6.8 feet away from the golf club.

3. Distance Where the Ball Returns to the Ground:
The ball returns to the ground when the height [tex]\( h(x) = 0 \)[/tex]. Solving the quadratic equation for [tex]\( x \)[/tex] when [tex]\( h(x) = 0 \)[/tex]:

[tex]\[ 0 = -0.25x^2 + 3.4x \][/tex]

Factoring out [tex]\( x \)[/tex]:

[tex]\[ 0 = x(-0.25x + 3.4) \][/tex]

This gives us two solutions:

[tex]\[ x = 0 \quad \text{or} \quad -0.25x + 3.4 = 0 \][/tex]

Solving the second equation for [tex]\( x \)[/tex]:

[tex]\[ -0.25x + 3.4 = 0 \implies x = \frac{3.4}{0.25} = 13.6 \][/tex]

Thus, the ball returns to the ground at about 13.6 feet away from the golf club.

In summary:
- The ball starts 0 feet above the ground.
- The ball reaches a maximum height of 11.6 feet at a horizontal distance of 6.8 feet away from the golf club it was hit with.
- The ball returns to the ground at about 13.6 feet away.